3 years ago

Solve for x. 9≤17−4x9≤17−4x

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

not sure that that can be solved

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Six times a number increased by 20 is four less than eight times the number. Find the number

DaniilM [7]

Greetings!

"Six times a number increased by 20 is four less than eight times the number. Find the number."...

This would be, as an equation:
 $6x+20=8x-4$

Solve:
Add 4 and -6x to both sides.
$(6x+20)+4+(-6x)=(8x-4)+4+(-6x)$
Simplify.
$24=2x$
Divide both sides by 2.
$(24)/2=(2x)/2$
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$12=x$
$x=12$

x=12

Hope this helps.
-Benjamin

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How to subtract hexadecimal number when one is bigger than the other?

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In order to be simple: let's code hexadecimal numbers on 4 digits.

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7a-7a=7a+44-7a
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no solutions

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