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zmey [24]
3 years ago
14

Find the value of X. Segment addition

Mathematics
1 answer:
Maru [420]3 years ago
3 0
X = 2.

Set up your equation like this:
3x + 4x = 14
7x = 14
x = 2

Hope this helped
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An electronics store makes a profit of $72.00 for every television sold and $90.00 for every computer sold. The manager’s target
viktelen [127]

Answer:

<h2>Option A, C and D is the three possible solution.</h2>

Step-by-step explanation:

Each Television earns $72 and each Computer earns $90.

The manager’s target is to make at least $360.00 a day.

It is <u>not clarified the exact number of Televisions and Computers</u>.

Hence, as per the given condition, 72x + 90y \geq  360\\8x + 10y \geq  40\\4x + 5y \geq  20.

Now we just need to check the given options, whether they satisfy the above equation, or not.

Except the option B, each inequality indicates a value greater than 360.

Hence, option B can not be the possible solution.

4 0
3 years ago
The owner of a snow cone stand used 1/4 gallon of syrup to make 16 cherry snow cones. She used the same amount of syrup in each.
Andreas93 [3]

Answer:

4 gallons

Step-by-step explanation: for each gallon she used one

5 0
3 years ago
Read 2 more answers
the area of the base of a pyramid is 18 square yards. the height of the pyramid is 5 yards what is the volume of the pyramid
nikitadnepr [17]
V=areax height
v=18x5
v=90
3 0
3 years ago
Solve the system of linear equations by substitution.<br> 2x-y=3<br> x+5y=14
Arturiano [62]

Answer:

x= 29/11 or y= 25/11

Step-by-step explanation:

2x - y= 3 ...........equation 1

x + 5y= 14 ............equation 2

Make x the subject of the formula in equation 2

x= 14 - 5y ..............equation 3

Substitute x=14 - 5y in equation 1

2(14- 5y) - y=3

28 - 10y - y=3

Collect like terms

-10y - y=3 - 28

-11y= -25

divide both sides by coefficient of y

-11y/-11 = -25/-11

y= 25/11

Substitute y= 25/11 in equation 3

x=14 - 5(25/11)

x= 14 - 125/11

x= 29/11

6 0
3 years ago
Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma
scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

315+213-123 =405

Out of 500 students 405 have taken either Math or Economics

Hence

c) student who have taken neither = 500-405 =95

Exactly one course is either math or economics - both

= 405-123 = 282

3 0
3 years ago
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