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Firlakuza [10]
2 years ago
7

A cylinder has a base radius of 6ft and a height of 18ft. What is its volume in cubic ft, round to the nearest tenth?

Mathematics
1 answer:
Nookie1986 [14]2 years ago
3 0

Answer:2034.7

Step-by-step explanation:

The equation is pi •r^2•h

R=6

H=18

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Acar can travel 25 miles per gallon. Approximately how many gallons of fuel will the car need to travel 30
FrozenT [24]

Answer:

The gallons of fuel car need to travel 30 km is <u>0.75</u> approximately .

Step-by-step explanation:

Given:

The car can travel 25 miles per gallon. (1 mile = 1.6 km)

Now, we need to convert 25 miles into km .

25 miles = 25 × 1.6 km

              = 40 km

So, the car can travel 40 km per gallon.

Then, we find out in 1 km how many gallons are used:

40 km = 1 gallons

1\ km = \frac{1}{40}\ gallons

1\ km = 0.025\ gallons

Now, we find out how much gallons of fuel will the car need to travel 30 km:

Gallons of fuel the car need to travel 30 km = 30\times 0.025

                                                                         = 0.75 gallons.

Therefore, the gallons of fuel car need to travel 30 km is 0.75 approximately.

6 0
3 years ago
Help me solve this please.​
poizon [28]
6, 7, 8, and 9. just plug the X into the equation
4 0
2 years ago
A field is to be fertilized at a cost of $0.08 per square yard. The rectangular part of the field is 95 yards long and the diame
dem82 [27]

this gives
total area of the field = 4655 sqyrd + 1884.79 sqyrd = 6539.79 sqyrd
 cost of fertilising 1 sqyrd = $ 0.08
 so cost of fertilising 6539.79 sqyrd = 6539.79 * $ 0.08 = $ 523.18

6 0
3 years ago
How do you choose between mean and median as the best measure for the center of a distribution?
OverLord2011 [107]
That would be the median I think...
7 0
2 years ago
Please help me solve this for 15 points! <br><br>-x2 + 4x - 54 = 0​
Mazyrski [523]

Answer:

x1 =2-5i*sqrt(2)

x2 =2+5i*sqrt(2)

Step-by-step explanation:

-x^2 +4x-54=0 (quadratic equation)

a=-1, b=4, c=-54

x1=(-b+sqrt(b^2-4ac))/2a

x1=(-4+sqrt(4^2 - 4*(-1)(-54))/2*(-1)

x1=(-4+sqrt(16-216))/(-2)

x1 =(-4+sqrt(-200))/(-2)

x1 =(-4+sqrt(200i^2))/(-2) i^2=-1

x1 =(-4+sqrt(100*2*i^2))/(-2)

x1 =(-4+10i*sqrt(2))/(-2)

x1 =2-5i*sqrt(2)

x2 =(-b-sqrt(b^2-4ac))/2a

x2 =(-4-10i*sqrt(2))/(-2)

x2 =2+5i*sqrt(2)

7 0
3 years ago
Read 2 more answers
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