your endpoints are correct, however recall that x² means (x)².
![\bf \begin{array}{cllll} ~~1\times [(-2)^2+8]\\\\ +1\times [(-1)^2+8]\\\\ +1\times [(0)^2+8]\\\\ +1\times [(1)^2+8] \end{array}\implies \begin{array}{llll} ~~4+8\\\\ +1+8\\\\ +0+8\\\\ +1+8 \end{array}\implies \begin{array}{cll} ~12\\ +9\\ +8\\ +9\\ \text{\textemdash\textemdash\textemdash}\\ 38 \end{array}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Cbegin%7Barray%7D%7Bcllll%7D%20~~1%5Ctimes%20%5B%28-2%29%5E2%2B8%5D%5C%5C%5C%5C%20%2B1%5Ctimes%20%5B%28-1%29%5E2%2B8%5D%5C%5C%5C%5C%20%2B1%5Ctimes%20%5B%280%29%5E2%2B8%5D%5C%5C%5C%5C%20%2B1%5Ctimes%20%5B%281%29%5E2%2B8%5D%20%5Cend%7Barray%7D%5Cimplies%20%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~4%2B8%5C%5C%5C%5C%20%2B1%2B8%5C%5C%5C%5C%20%2B0%2B8%5C%5C%5C%5C%20%2B1%2B8%20%5Cend%7Barray%7D%5Cimplies%20%20%5Cbegin%7Barray%7D%7Bcll%7D%20~12%5C%5C%20%2B9%5C%5C%20%2B8%5C%5C%20%2B9%5C%5C%20%5Ctext%7B%5Ctextemdash%5Ctextemdash%5Ctextemdash%7D%5C%5C%2038%20%5Cend%7Barray%7D%20)
Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of
0
.
2
x
-
3
2
x
2
-
3
x
+
5
Divide the highest order term in the dividend
2
x
2
by the highest order term in divisor
2
x
.
x
2
x
-
3
2
x
2
-
3
x
+
5
Multiply the new quotient term by the divisor.
x
2
x
-
3
2
x
2
-
3
x
+
5
+
2
x
2
-
3
x
The expression needs to be subtracted from the dividend, so change all the signs in
2
x
2
−
3
x
x
2
x
-
3
2
x
2
-
3
x
+
5
-
2
x
2
+
3
x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
x
2
x
-
3
2
x
2
-
3
x
+
5
-
2
x
2
+
3
x
0
Pull the next term from the original dividend down into the current dividend.
x
2
x
-
3
2
x
2
-
3
x
+
5
-
2
x
2
+
3
x
0
+
5
The final answer is the quotient plus the remainder over the divisor.
x
+
5
2
x
−
3
Answer:
-2 2/5
Step-by-step explanation:
- 3/5 + - 9/5 = -12/5
-12/5 = -2 2/5
Answer:Number of coins that are quarters =60
Step-by-step explanation:
Total coins in possession of Eric=240
Number of coins that are pennies=11\20 x 240= 132
Number of coins that are nickels=4\20 x 240= 48
Since the rest are quarters,
Number of coins that are quarters =Total coins in possession of Eric -( Number of coins that are pennies+ Number of coins that are nickels)
=240-(132+48)
=240-180
=60
(1,1) because x + 2y <4
=1 + 2(1)
= 3 which is less than 4
