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AveGali [126]
3 years ago
12

What is 1483+2942838

Mathematics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer: 2,944,321

Step-by-step explanation: Use long addition and evaluate.

Hope this helps you out! ☺

-Leif Jonsi-

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Please help me anyone ;(
Sergio039 [100]

Answer:

9 tables

Step-by-step explanation:

All we have to do is see how many time 6³/₄ ft. can fit in 60³/₄ ft. through division.

60 ³/₄ ÷ 6 ³/₄ =

²⁴³/₄ ÷ ²⁷/₄ =

²⁴³/₄ × ⁴/₂₇ =

²⁴³/₂₇ =

9 tables

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3 years ago
​For the two right triangles above, explain why
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Answer:

we cant see the triangles

Step-by-step explanation:

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3 years ago
Find the median of the set of data. <br><br> 4, 16, 7, 10, 15, 11, 13, 20
Rainbow [258]
The median is twelve [12]. 
8 0
3 years ago
Read 2 more answers
Use the Chain Rule to find the indicated partial derivatives. u = x2 + yz, x = pr cos(θ), y = pr sin(θ), z = p + r; (partial u)/
devlian [24]

u(x,y,z)=x^2+yz

\begin{cases}x(p,r,\theta)=pr\cos\theta\\y(p,r,\theta)=pr\sin\theta\\z(p,r,\theta)=p+r\end{cases}

At the point (p,r,\theta)=(2,2,0), we have

\begin{cases}x(2,2,0)=4\\y(2,2,0)=0\\z(2,2,0)=4\end{cases}

Denote by f_x:=\dfrac{\partial f}{\partial x} the partial derivative of a function f with respect to the variable x. We have

\begin{cases}u_x=2x\\u_y=z\\u_z=y\end{cases}

The Jacobian is

\begin{bmatrix}x_p&x_r&x_\theta\\y_p&y_r&y_\theta\\z_p&z_r&z_\theta\end{bmatrix}=\begin{bmatrix}r\cos\theta&p\cos\theta&-pr\sin\theta\\r\sin\theta&p\sin\theta&pr\cos\theta\\1&1&0\end{bmatrix}

By the chain rule,

u_p=u_xx_p+u_yy_p+u_zz_p=2xr\cos\theta+zr\sin\theta+y

u_p(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_p(2,2,0)=16}

u_r=u_xx_r+u_yy_r+u_zz_r=2xp\cos\theta+zp\sin\theta+y

u_r(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_r(2,2,0)=16}

u_\theta=u_xx_\theta+u_yy_\theta+u_zz_\theta=-2xpr\sin\theta+zpr\cos\theta

u_\theta(2,2,0)=-2\cdot4\cdot2\cdot2\sin0+4\cdot2\cdot2\cos0\implies\boxed{u_\theta(2,2,0)=16}

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3 years ago
PLEASE HELP!!! ill give you brainliest
Orlov [11]

Answer:43 teaches

Step-by-step explanation:I research it

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