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Elden [556K]
3 years ago
13

Find the median of the set of data. 4, 16, 7, 10, 15, 11, 13, 20

Mathematics
2 answers:
Rainbow [258]3 years ago
8 0
The median is twelve [12]. 
Ede4ka [16]3 years ago
5 0

The median is when you add the set of numbers, then divide it by the number of numbers in the set.

4+16+7+10+15+11+13+20=96

then divide 96 by the number of numbers. 96/8= 12, that is the median

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A sales person told Hannah she could buy the computer on an installment plan. She
VashaNatasha [74]

Answer:

She would be paying $2,622 total.

Step-by-step explanation:

1. To get how much she'd be paying for 24 months, all you have to do is multiply 24 times 95.

2. To get the down payment you had to ask yourself what's 15% of 2,280. 15% of 2280 is 342.

3. Add those together and you'd get the total payment.

Simple.

Oh and gimme Brainliest if it's correct.

6 0
3 years ago
Felipe made $168 for 8 hours of work. At the same rate, how much would he make for 18 hours of work?
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Answer: $378

Step-by-step explanation: 18/8=2.25

Multiply 2.25 and 168 to get 378

3 0
3 years ago
Diana can type 100 form letters
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Answer:

it will take 3 hours long

8 0
3 years ago
Selma's class is making care packages to give to victims of a natural disaster. Selma packs one box in 5 minutes and has already
Monica [59]
66 more min. he used which could be 1 hour and 6 min.
7 0
3 years ago
Read 2 more answers
Twelve percent of U.S. residents are in their forties. Consider a group of nine U.S. residents selected at random. Find the prob
miskamm [114]

Answer:

The probability is 28 % ( approx )

Step-by-step explanation:

Since, there are only two possible outcomes in every trails ( residents are in their forties or not ),

So, this is a binomial distribution,

Binomial distribution formula,

Probability of success in x trials,

P(x)=^nC_x p^x q^{n-x}

Where, ^nC_x=\frac{n!}{x!(n-x)!}

p and q are probability of success and failure respectively and n is the total number of trials.

Let X be the event of resident who are in his or her forties.

Here, p = 12% = 0.12,

⇒ q = 1 - p = 1 - 0.12 = 0.88,

n = 9,

Hence, the probability that two or three of the people in the group are in their forties = P(X=2) + P(X=3)

^9C_2 (0.12)^2 (0.88)^{9-2}+^9C_3 (0.12)^3 (0.88)^{9-3}

=36(0.12)^2 (0.88)^7+84(0.12)^3 (0.88)^6

=0.279266611163

\approx 0.28

=28\%

7 0
3 years ago
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