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Romashka-Z-Leto [24]

2 years ago

7

A loan used for buying a home is called a mortgage.The Carey family is buying a $250,00 home. They are taking out a 15-year mort

gage at a rate of 5.75%

1 answer:

777dan777 [17]2 years ago

3 0

Answer:

2500

Step-by-step explanation:

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15a+2-7<br> What are the terms, like terms, coefficients, and constants in this equation?

Elenna [48]

15 is coefficient, a is a variable, 2 and -7 are like terms, 15a is a term and 2 and 7 are constants.

5 0

2 years ago

Work out giving your answer in its simpliest form 2/3 × 3 3/5<br>help asap I will give brainlist

Anna11 [10]

Answer:

2 2/5 or 12/5

Step-by-step explanation:

Hope this helps :)

5 0

2 years ago

Read 2 more answers

A single card is drawn at random from a standard 52 card deck. Work out in its simplest

larisa [96]

Answer:

1/52

Step-by-step explanation:

8 0

3 years ago

Members of video game platform X-

Natalija [7]

Answer:

When number of games downloaded is at least 3

Step-by-step explanation:

Let x = number of games downloaded

Members = 50 + 2x

Non members = 20x

50 + 2x = 20x

50 = 20x - 2x

50 = 18x

x = 50/18

x = 2.78

At x = 2.78, both members and non members are paying the same amount

For members to make profits, the value of x must be greater than 2.78

Approximately x = 3

Check:

Members = 50 + 2x

= 50 + 2(3)

= 50 + 6

= 56

Non members = 20x

= 20(3)

= 60

3 0

2 years ago

Circle O has a center at (-2, 10) and a

allsm [11]

Answer:

B

Step-by-step explanation:

If the point lies on the circle, the distance of the point to the center would be equivalent to the circle's radius since radius is defined as the distance from the center to any point of the circle.

Since length of a radius is half of a diameter,

radius= diameter ÷2

radius= 12 ÷2

radius= 6 units

Let's find the length between each points to see which is equal to 6 units, using the distance formula below.

$distance = \sqrt{(y1 - y2)^{2} + {(x1 - x2)}^{2} }$

A. Distance between 2 points

$= \sqrt{ {(10 + 5)}^{2} + ( - 2 + 6)^{2} } \\ = \sqrt{15 ^{2} + {4}^{2}} \\ = \sqrt{241} \\ = 15.524 \: units$

(to 5 s.f.)

Since the distance is greater than 6 units, point A lies outside the circle.

B. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + ( - 2 + 2)^{2} } \\ = \sqrt{ {6}^{2} } \\ = 6 \: units$

Since the distance of B from the center is 6 units, point B lies on Circle O.

Let's check the other 2 points:

C. Distance between 2 points

$= \sqrt{ {(10 - 4)}^{2} + {( - 2 - 6)}^{2} } \\ = \sqrt{ {6}^{2} + ( - 8)^{2} } \\ = \sqrt{100} \\ = 10 \: units$

Since the distance of point C from the center is greater than 6 units, point C lies outside the circle.

D. Distance between 2 points

$= \sqrt{ {(10 - 8)}^{2} + {( - 2 - 8)}^{2} } \\ = \sqrt{2^{2} + ( - 10)^{2} } \\ = \sqrt{104} \\ = 10.198 \: units$

(to 5 s.f.)

Point D also lies outside Circle O.

8 0

3 years ago