Probability = (number of ways to succeed) / (total possible outcomes) .
The total possible results of rolling two dice is
(6 on the first cube) x (6 on the second one) = 36 possibilities.
How many are successful ? I need you to clarify something first.
You said that the 'second die' shows an odd number. When a pair
of dice is rolled, the problem usually doesn't distinguish between them.
And in fact, you said that they're "tossed together" (like a spinach and
arugula salad ?) so I would understand that they would lose their identity
unless they were, say, painted different colors, and we wouldn't know
which one is the second one.
Oh well, I'll just work it both ways:
First way:
Two identical dice are tossed.
The total is 5 and ONE cube shows an odd number.
How can that happen ?
1 ... 4
4 ... 1
3 ... 2
2 ... 3
Four possibilities. Probability = 4/36 = 1/9 = 11.1% .
=======================================
Second way:
A black and a white cube are tossed together.
The total is 5 and the white cube shows an odd number.
How can that happen:
B ... W
4 .... 1
2 .... 3
Only two possibilities. Probability = 2/36 = 1/18 = 5.6% .
First you add 3+6, then take 9 and multiply by 2 which is 18, the do 26-18 which is 8×3=24.
12×3=36-12=24.
So 24=24
Your answer is A.
Answer: 30 students per bus
Step-by-step explanation: 99-9=90
90/3=30
30 students per bus
220% is 2.20 in decimal form in fraction 2 1/5
Answer:
Step-by-step explanation:
Given parameters:
Number of white balls = 24
Number of black balls = 16
Unknown:
The probability that white ball is drawn at random = ?
Solution:
The probability of an event is the likelihood of such an event to occur. That an event will occur has a probability of 1, it will not occur have a probability of zero.
In this problem, the total number of outcomes of drawing any ball has sample space of (24 + 16)outcomes = 40outcomes.
Probability of an event = 
Pr(white balls) = 
=
