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Romashka [77]
4 years ago
11

milton opens a store credit card when he purchases appliances for his kitchen. the interest rate is 17.45%. he charges $3,740 to

the card, and can pay $1,350 per month. What will the total cost of his purchase be?
Mathematics
1 answer:
kari74 [83]4 years ago
3 0

<u>Answer-</u>

The total cost of his purchase will be $3,846.34

<u>Solution-</u>

Here, the annual interest rate is 17.45%.

So monthly interest rate will be,

=\frac{17.45}{12} =1.454\%=0.01454

With a purchase of $3,740, the amount will be after one month,

=3740(1+0.01454)^1=3740(1.01454)=3794.38

Then she makes a payment of $1350, so the balance at the end of month 1 is

=3794.38-1350=2444.37

Now she has to pay with $2444.37 as principal amount, the amount will be after one month,

=2444.37(1+0.01454)^1=2444.37(1.01454)=2479.91

Then she again makes a payment of $1350, so the balance at the end of month 2 is

=2479.91-1350=1129.91  

Final month, she has to pay with $1129.91 as principal amount, the amount will be,

=1129.91(1+0.01454)^1=1129.91(1.01454)=1146.34

So the total cost, including interest, would be the sum of the three payments,

=1350+1350+1146.34=3,846.34

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3 years ago
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3 years ago
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luda_lava [24]

Answer:

z=\frac{0.939 -0.87}{\sqrt{\frac{0.87(1-0.87)}{115}}}=2.20  

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For this case since the p value is lower than the significance level provided \alpha=0.05 we have enough evidence to reject the null hypothesis and we can conclude that hotel chains customers are more satisfied with their service

Step-by-step explanation:

Information given

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X=108 represent the  number of people who were satisfied with their service

\hat p=\frac{108}{115}=0.939 estimated proportion of people who were satisfied with their service

p_o=0.87 is the value that we want to test

\alpha=0.05 represent the significance level

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We want to verify if hotel chains customers are more satisfied with their service.:  

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The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.939 -0.87}{\sqrt{\frac{0.87(1-0.87)}{115}}}=2.20  

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For this case since the p value is lower than the significance level provided \alpha=0.05 we have enough evidence to reject the null hypothesis and we can conclude that hotel chains customers are more satisfied with their service

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Answer correctly for Brainliest!!
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Step-by-step explanation:

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If possible, pls give brainliest. tks

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