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3 years ago

In an arithmetic series, what is the sum of the first 22 terms if the first term is 12 and the common difference is 3?

Mathematics

1 answer:

Vilka [71]3 years ago

4 0

Answer:

561

Step-by-step explanation:

an = dn - (a-d)

The difference is 3.

The first term is 12.

an = 3n - (12-3)

an = 3n - 9

Put n as 1, 2, 3, 4, 5 ....22.

3(1) - 9 = -6

3(2) - 9 = -3

3(3) - 9 = 0

3(4) - 9 = 3

3(5) - 9 = 6

...

3(22) - 9 = 57

Add the first 22 terms.

-6+-3+0+3+6+9+12+15+18+21+24+27+30+33+36+39+42+45+48+51+54+57

= 561

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2 years ago

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Step-by-step explanation:

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Hope this helps.!

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3 years ago

Read 2 more answers

I'll give you more points but you have to answer all the parts to the question. I need this plsssss ty lol. Show all work too pl

alexira [117]

Answer:

a) 34mi

b) 10mi

c) 44mi

d) by Calculating the amount of miles it would take John to go to school plus the amount of miles it would take Sara to go to school. Then add the sum of the amount of miles it took for both to go to school.

Step-by-step explanation:

a) explanation:

$a^{2} +b^2=c^2$

$16^2+30^2=c^2$

$256 + 900 = c^2$

$c^2=1156$

$\sqrt{1156}=34mi$

b) explanation:

$a^{2} +b^2=c^2$

$6^2+8^2=c^2$

$36+64=c^2$

$c^2=100$

$\sqrt{100} =10mi$

c) explanation: we already have all the data from John's house to Sara's House.

John's House to Sara's House = John's House to School + Sara's House to School.

Sara's House to School (Question #1) = 34mi

John's House to School (Question #2) = 10mi

34(mi) + 10(mi) = 44(mi)

d) explanation: explanation is on the answer

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3 years ago