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seraphim [82]
3 years ago
6

For the given functions, f(x) and g(x) find f(x)+g(x)

Mathematics
1 answer:
Nitella [24]3 years ago
4 0

Answer: -5.5x - 1.167


Step-by-step explanation:

lets focus on the top part of the fraction, remember were allowed to just add the top together because the bases are the same

okay, so the variables we know we can combine are 8x and 3x which equals 11x and -13 and 41 which equals 28

so now our top looks like x^2 +11x + 28, all over x^2- 2x - 24

we can cancel out the X^2, and from then its just a division problem

you end up with -5.5x - 1.167

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fiasKO [112]

9514 1404 393

Answer:

  • plurality: San Francisco
  • plurality with elimination: New York

Step-by-step explanation:

Using the plurality method, the city with the most first-place votes wins the selection. Here, that is San Francisco, with 16 votes. Behind that is New York with 14 first-place votes.

If elimination is used, the selection with the fewest first-place votes (Chicago) is eliminated from the table, and all rows below are shifted up. Now, the first place row has 16 votes for San Francisco and 18 votes for New York.

San Francisco wins the plurality election.

New York wins the plurality-with-elimination election.

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2 years ago
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3 years ago
Write the slope-intercept form of the equation of the line.<br> slope = 0, y - int=1
saveliy_v [14]

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y= 1

Step-by-step explanation:

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Hope This Helps :)

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3 years ago
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Gia opened two savings accounts at two different banks. One account earns an annual 3.4% simple interest, and the other earns ha
Harlamova29_29 [7]

Answer:

The correct option is;

A. $76.50

Step-by-step explanation:

To solve the question, we note the formula for simple interest = Principal × Rate × Time/100

That is

S.I. = \frac{Principal \times Rate \times Time}{100} = \frac{P \times R \times T}{100}

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P = Principal Amount = $500.00

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S.I. = \frac{500 \times 3.4 \times 3}{100} = \$51

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P = Principal Amount = $500.00

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Therefore, the total interest she have earned in three years is $51 + $25.5 = $76.5

6 0
3 years ago
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