Answer:
1. x= -56.25
Expand
19.5-6.5x+36=201-4.5x-33
Simplify
-6.5x+55.5=201-4.5x-33
Simplify again
6.5x+55.5=-4.5x+168
Add 6.5 to both sides
55.5=-4.5x+168+6.5x
Simplify
55.5=2x+168
Subtract
55.5-168=2x
Simplify
112.5=2x
Divide both sides by 2
−112.5÷2 = x
Simplfy
x = -56.25
2. x > -7 ÷ 4
Or
Decimal Form: -1.75
Remove parentheses
12x>4x+5−19
Simplify
12x>4x-14
Subtract
12x-4x>-14
Simplify
8x>-14
Divide both sides by 8
x > -14 ÷ 8
Simplify
x > -7 ÷ 4
Or
Decimal Form: -1.75
3. Answer: Step 2 has an error
Step-by-step explanation:
Given equation,
2(10 - 13x) = -34x + 60
By distributive property,
20 - 26x = -34x + 60
Now, we need to isolate x on the left side of the equation,
For this we need to eliminate constant term from the left side,
20 will be eliminated by subtracting 20 from both sides ( subtraction property of equality )
I.e. Step 2 has an error,
We need to use subtraction property of equality instead of using addition property of Equality,
Note : The correct steps would be,
Step 2 : 20 - 26x = -34x + 60 ( Subtraction property of equality )
Step 3 : 8x = 40 ( addition property of Equality )
Step 4 : x = 5 ( Division Property of Equality )
Hope this helps!!! Good luck!!! ;)
<span>10 units to the right and 2 units up,</span>
Answer:
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s = 3.26 m/s.
Step-by-step explanation:
Let's analyze each case.
93.4 g/mL x 20. mL
Hewe we are multiplying g/ml*ml. So we have the answer is (g*ml/ml) = g.
So
93.4 g/mL x 20. mL = 1868g.
489.7m / 53.061 s
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
489.7m / 53.061 s = 9.23 m/s
216.3 m/66.4 s
Same as above.
We are dividing a measurement in m by a measurement in s. So the answer is in m/s.
So
216.3 m/66.4 s = 3.26 m/s.
Answer:
Mark point E where the circle intersects segment BC
Step-by-step explanation:
Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.
Bill's next step is to mark point E, so he can use it as the center of one of the circles just described.
___
<em>Comment on Bill's "technology"</em>
In the technology I would use for this purpose, the next step would be "select the angle bisector tool."
Well you can start by drawing a triangle with the information
the size of angle B can be found using the Law of Sine
the size of angle C can be found using angle sum of a triangle.
The length of side c can be found using the Law of Cosines
hope it helps
