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2 years ago

determine the mean of the numbers 7, 5, 5, 2, 8 and 7. if two additional numbers 2 and x, reduce the mean by 1, find x

1 answer:

4 0

(7 + 5 + 5 + 2 + 8 + 7) / 6 = 34/6 = 5.67

(34 + 2 + x) / 8 = 5.67 - 1
(36 + x) / 8 = 4.67
36 + x = 4.67 * 8
36 + x = 37.36
x = 37.36 - 36
x = 1.36

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Markus was given dollar bills from his grandfather each day for one week. On the first day he received $1, on the second day he

snow_tiger [21]

Answer: $127.00

Step-by-step explanation:

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2 years ago

Find the inverse of the given function.

kodGreya [7K]

For this case we must find the inverse of the following function:

$f (x) = - \frac {1} {2} \sqrt {x + 3}$

We follow the steps below:

Replace f(x) with y:

$y = -\frac {1} {2} \sqrt {x + 3}$

We exchange the variables:

$x = - \frac {1} {2} \sqrt {y + 3}$

We solve for "y":

$- \frac {1} {2} \sqrt {y + 3} = x$

Multiply by -2 on both sides of the equation:

$\sqrt {y + 3} = - 2x$

We raise both sides of the equation to the square to eliminate the radical:

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We subtract 3 from both sides of the equation:

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We change y by f ^ {- 1} (x):

$f ^ {- 1} (x) = 4x ^ 2-3$

Answer: $f ^ {- 1} (x) = 4x ^ 2-3$

7 0

3 years ago

Read 2 more answers

Megan charges %5.00 for each hour, (h), she babysits. Last week, the total amount she earned by babysitting was $65.00.

mel-nik [20]

Answer:

Step-by-step explanation:

To find how many hours she worked you must divide $65 by $5 and B is the only equation where you can do that.

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2 years ago

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),

pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

$\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}$

$(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}$