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2 years ago

HELP HELP HELP OMGOMG

Mathematics

1 answer:

user100 [1]2 years ago

6 0

Answer:

Direct variation

Step-by-step explanation:

It's not iverse because the line is curved so it's direct variation

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Find the coordinates of the midpoint of a segment with the given

galben [10]

Answer:

(9,5.5)

Step-by-step explanation:

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2 years ago

What are the solutions of the quadratic equation? Solve by factoring. 4x^2-18x+20=0

Romashka-Z-Leto [24]

Answer:

x = 5/2,2

Step-by-step explanation:

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2 years ago

DEAR SIRS AND MISSES, PLEASE HELP ME!

GaryK [48]

Volume of a cone= $\pi$ r^2*h/3
$\pi$ *3^2*6/3=56.55

volume fo a sphere = 4/3 $\pi$ r^3
4/3*pi*1.5^3=14.14

56.55-14.14=42.41

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2 years ago

How to simplify this expression

dexar [7]

Answer:

$\dfrac{x+2}{x+1}$

Step-by-step explanation:

Factor the numerator and cancel common factors from numerator and denominator.

$\dfrac{x^2-4}{(x-2)(x+1)}=\dfrac{(x-2)(x+2)}{(x-2)(x+1)}=\dfrac{x+2}{x+1}$

5 0

2 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: