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3 years ago

A Large school wants to put a clock in each of its 224 classrooms

2 answers:

4 0

the school wants to get 224 clocks, they clocks come in packs of 14, so each pack has 14 clocks, how many packs are needed?

well, how many times does 14 go into 224? 224 ÷ 14, and you know what that is.

WITCHER [35]3 years ago

3 0

Answer:

16 packs

Step-by-step explanation:

u just have to divide 224 by 14 to get 16

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What is the value of x? round the answer to the nearest tenth. the diagram is not drawn to scale.

Zepler [3.9K]

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8 0

3 years ago

Read 2 more answers

Karl is making a pot of chili. The recipe calls for StartFraction 3 Over 8 EndFraction cup of chili powder, but Karl only wants

mina [271]

Given:

The recipe calls for $\dfrac{3}{8}$ cup of chili powder.

Karl only wants to use half as much so it won’t be so spicy.

To find:

How much chili powder should Karl use?

Solution:

We have,

Chill power for recipe = $\dfrac{3}{8}$ cup

Chill power used by Karl is half of chill power for recipe.

$\text{Chill power used by Karl}=\dfrac{1}{2}\times \dfrac{3}{8}$ cup $\text{Chill power used by Karl}=\dfrac{3}{16}$ cup

Therefore, $\dfrac{3}{16}$ cup of chili powder should Karl use.

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3 years ago

What do you think the value of represents in the function? How can you predict what the graph of a quadrati function will look l

allochka39001 [22]

Answer:

Step-by-step explanation:

Parts of the question are missing.

y = a(x-h)² + k is a vertical parabola.

If a is positive, the parabola opens upwards.

If a is negative, the parabola opens downwards.

The vertex is at (h, k)

7 0

3 years ago

PLS HELPPPP MEEE <br> (explain ur answer)

adell [148]

Answer:

<em>(4). is the correct answer</em>

Step-by-step explanation:

(- 3, 1, 1)

(1). - 3 - 1 - 1 ≠ - 2 not an answer...

(2). - 3 - 1 + 3(1) ≠ 2 not an answer...

(3). 4( - 3) + 1 - 3(1) ≠ - 4 not an answer...

<em>(4). 2(- 3) + 3(1) + 4(1) = 1 </em>

<em>3(1) + 3(1) = 6 </em>

<em>- 3 = - 3(1) </em>

7 0

3 years ago

(csc x - 1) (csc x + 1)

victus00 [196]

<h2>Explanation:</h2>

Here we have the following expression:

$(csc x - 1) (csc x + 1)$

So we need to extend this. Remember that the difference of squares tells us:

$(a-b)(a+b)=a^2-b^2$

So here:

$a=cscx \\ \\ b=1$

Thus:

$(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}$

4 0

3 years ago