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kramer
3 years ago
6

leo takes 30 minutes to eat dinner 15 minutes to change clothes and 20 minutes to walk to practice.if leo needs to be at hockey

practice at 7:15 pm what time does he need to begin
Mathematics
2 answers:
KIM [24]3 years ago
6 0
6:10 pm if you want to be exact 

liq [111]3 years ago
5 0
Hi there, first let's add up the minutes, 30 minutes+15 minutes+20 minutes equals 65 minutes, 65 minutes equals 1 hour and 5 minutes. 7:15 pm, an hour before that is 6:15, 5 minutes before that is 6:10. Therefore, Leo needs to begin at 6:10 pm
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Y=5^× what happens as the x value increases by 1​
Allisa [31]

Answer:

Step-by-step explanation:

It continues to go up in the positive X and Y Axis. Like an exponential function

8 0
3 years ago
A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace
Alex787 [66]
D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154

Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20


5 0
3 years ago
HELPPPPPPPPPPPPPPPPP
emmasim [6.3K]
For this case, what you should see is where the graph cuts the x-axis.
 Notice that the graph cuts to the x axis in three different points.
 Then the value of x that is in the domain of the function in this case is:
 x = 1
 For this value of x the function is zero.
 Answer:
 x = 1
5 0
3 years ago
Read 2 more answers
The system of equations may have a unique solution, an infinite number of solutions, or no solution. Use matrices to find the ge
Leno4ka [110]

Answer:

Infinite number of solutions.

Step-by-step explanation:

We are given system of equations

5x+4y+5z=-1

x+y+2z=1

2x+y-z=-3

Firs we find determinant of system of equations

Let a matrix A=\left[\begin{array}{ccc}5&4&5\\1&1&2\\2&1&-1\end{array}\right] and B=\left[\begin{array}{ccc}-1\\1\\-3\end{array}\right]

\mid A\mid=\begin{vmatrix}5&4&5\\1&1&2\\2&1&-1\end{vmatrix}

\mid A\mid=5(-1-2)-4(-1-4)+5(1-2)=-15+20-5=0

Determinant of given system of equation is zero therefore, the general solution of system of equation is many solution or no solution.

We are finding rank of matrix

Apply R_1\rightarrow R_1-4R_2 and R_3\rightarrow R_3-2R_2

\left[\begin{array}{ccc}1&0&1\\1&1&2\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\1\\-5\end{array}\right]

ApplyR_2\rightarrow R_2-R_1

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&-1&-3\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\-5\end{array}\right]

Apply R_3\rightarrow R_3+R_2

\left[\begin{array}{ccc}1&0&1\\0&1&1\\0&0&-2\end{array}\right]:\left[\begin{array}{ccc}-5\\6\\1\end{array}\right]

Apply R_3\rightarrow- \frac{1}{2} and R_2\rightarrow R_2-R_3

\left[\begin{array}{ccc}1&0&1\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-5\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Apply R_1\rightarrow R_1-R_3

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]:\left[\begin{array}{ccc}-\frac{9}{2}\\\frac{13}{2}\\-\frac{1}{2}\end{array}\right]

Rank of matrix A and B are equal.Therefore, matrix A has infinite number of solutions.

Therefore, rank of matrix is equal to rank of B.

4 0
3 years ago
The set of types of matter<br>well difined or not​
Tresset [83]

Answer:

It is not well defined.

Step-by-step explanation:

Because set is a collection of well defined objet. And matter contains of solid, liquid and gas

3 0
3 years ago
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