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3 years ago

14

PLEASE HELP, THIS IS VERY IMPORTANT!!!

2 answers:

serious [3.7K]3 years ago

6 0

<span>10.What expression is equivalent to the amount Miko paid?

A) 16 + 1.18
B) 1 + 1.18(16)
C) (16 + 0.18)16
<span>D) 16 + 0.18(16)

9. </span></span>2.75

8. 22 seconds with 23 min<span>
7. </span><span>0.00892857142

6. -0.48

5. can't do it

4. 8.16 cm

3. </span>-3.42857142857
2. 8.3333

1. -1.75

ANTONII [103]3 years ago

3 0

10.<em>D) 16 + 0.18(16)</em>

9. 2.75

8. 22 seconds with 23 min

7. 0.00892857142

6. -0.48

5. IDK =(

4. 8.16 cm

3. -3.42857142857

2. 8.3333

1. -1.75

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PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK

Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

$\sf \cos(\theta)=\dfrac{A}{H}$

where:

$\theta$ is the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Given:

$\theta$ = ∠KLM
A = LN = 8
H = KL = 15.2

$\implies \sf \cos(KLM)=\dfrac{8}{15.2}$

$\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)$

$\implies \sf \angle KLM=58.24313614^{\circ}$

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}$

Given:

r = 15.2
∠KLM = 58.24313614°

$\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)$

$\implies \textsf{Arc length MK}=\sf 15.45132428\:units$

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