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2 years ago

PLZZZZZZ NEED HELP!!!!!!!

Mathematics

1 answer:

tatyana61 [14]2 years ago

3 0

The answer is (4,-3.4)

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A path 1 m wide is build around a garden that is a 30-meter square. What is the area taken by the path?

maria [59]

Length of outer boundary =30m

So area of outer boundary =30×30

= 900m²

Length of inner boundary of path=30-1= 29m

Inner area =29×29 =841m²

So area of path is= outer area - inner area

=900- 841

= 59m²

6 0

1 year ago

Somebody explain pls!!!!!

Furkat [3]

Step-by-step explanation:

Using log properties

$log_{7}(rz {}^{12} )$

$log_{7}(r) + log_{7}(z {}^{12} )$

Then

$log_{7}(r) + 12 log_{7}(z)$

Plug in the knowns

$- 7.87 + 12( - 12.59)$

$- 158.95$

5 0

5 months ago

Which of the following shows the additive inverse of 4?*

spayn [35]

C is the correct answer I think

3 0

2 years ago

GIVING BRAINLIEST! A rectangular garden has a width of 10 feet and a length of 14 feet. A cement walkway is added around the out

Serjik [45]

Given:

Width of a garden = 10 feet

Length of the garden = 14 feet

Area of the garden and the walkway together = 396 square feet.

To find:

The width of the walkway.

Solution:

A cement walkway is added around the outside of the garden.

Let x be the width of the walkway.

The width of the garden with walkway = 10+2x

The length of the garden with walkway = 14+2x

Area of a rectangle is

$Area=length\times width$

Area of garden and the walkway together is

$Area=(14+2x)\times (10+2x)$

$396=140+28x+20x+4x^2$

$396=140+48x+4x^2$

$396=4(35+12x+x^2)$

Divide both sides by 4.

$99=35+12x+x^2$

$0=35-99+12x+x^2$

$0=-64+12x+x^2$

Splitting the middle term, we get

$x^2+16x-4x-64=0$

$x(x+16)-4(x+16)=0$

$(x+16)(x-4)=0$

Using zero product property, we get

$(x+16)=0\text{ and }(x-4)=0$

$x=-16\text{ and }x=4$

Width of walkway cannot be negative. So, x=4.

Therefore, the width of the walkways is 4 feet.

6 0

2 years ago

Read 2 more answers

Im absolutely clueless with part b and c

Elden [556K]

Answer:

19.8 and 8/(sin(theta))+ 6/(cos(theta))

Step-by-step explanation:

If you make a table you can see that L_1 + L_2 gets larger as you increase theta prom pi/2 and decrease theta from pi/2. This means that pi/2 is the theta that will yield the smallest length for the ladder. Plugging this into L_1 + L_2 you get 19.8 (rounded to the nearest hundred)

C = 8/(sin(theta))+ 6/(cos(theta))

7 0

3 years ago