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Zigmanuir [339]
3 years ago
13

Write the equation in standard form using integers: y = -2/5x - 3

Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0
Let's assume you meant y = (-2/5)x - 3.  

-2/5x could be misinterpreted.

First, clear out the fraction(s).  To do this, mult. both sides of the above eq'n by 5.  

Result:  5y= -2x - 15.  Add 2x to both sides.  The resulting equation is what you wanted:  an equation in the form Ax + By = C (standard form).
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Solution set for (6y+4)-(3+5y)=9
loris [4]
Y = 8 hoped it helped!
4 0
3 years ago
A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a
zavuch27 [327]

Answer:

Area = 3\dfrac{15}{16}\ sq\ ft

Area is greater than 3\frac{1}{2} sq ft.

Step-by-step explanation:

Length of rectangular sign board = 3\frac{1}{2} ft

Width of rectangular sign board = 1\frac{1}{8} ft

Area of a rectangle is given by the formula:

A = Length \times Width

To find the area, we are going to multiply 3\frac{1}{2} with 1\frac{1}{8}.

1\frac{1}{8} is greater than 1.

Therefore the multiplication will be greater than 3\frac{1}{2}.

Hence, we can say that area will be greater than 3\frac{1}{2} sq ft.

Area of the sign:

A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft

8 0
3 years ago
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
3 years ago
Which set of ordered pairs represents a function?
Mrac [35]
The second one because for every x value there is one and only one y value. If you plotted the points and graphed it, you would know it is not a function if it doesn't pass the vertical line test. Notice the same x values show up repeatedly in the other ordered pairs with different y values. Only one y value for every x value
5 0
3 years ago
Which of the following is NOT equal to sin pi/3
Yanka [14]

Answer:

D)  sin(\frac{4\pi }{3} ) = sin(\pi +\frac{\pi }{3} ) = -sin\frac{\pi }{3}

Step-by-step explanation:

A)

sin(\frac{2\pi }{3} ) = sin ( \pi - \frac{\pi }{3} ) = sin\frac{\pi }{3}

B)

cos (\frac{\pi }{6} ) = cos ( \frac{\pi }{2} - \frac{\pi }{3} ) = sin(\frac{\pi }{3})

C)

cos (\frac{11\pi }{6} ) = cos ( \frac{3\pi }{2} + \frac{\pi }{3} ) = sin(\frac{\pi }{3})

D)

 sin(\frac{4\pi }{3} ) = sin(\pi +\frac{\pi }{3} ) = -sin\frac{\pi }{3}

8 0
3 years ago
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