Write the following decimal number in it’s equivalent fraction form. Show all work for full credit. -0.6

The distance a race car travels is given by the equation d=v0t+12at2 where v0 is the initial speed of the race car, a is the acc

Scrat [10]

Answer:

v0 + 1/2at

Step-by-step explanation: Given that the distance a race car travels is given by the equation d = v0t+12at2 where v0 is the initial speed of the race car, a is the acceleration, and t is the time travelled.

The equation for the driver's average speed s during the acceleration will be:

(v0t+12at2) / t

Since Average speed is equal to distance divided by time.

Therefore, the equation will be:

v0+1/2at

7 0

3 years ago

In the circle below, chord AB passes through the center of circle 0. If the radius OC is perpendicular to chord AB and has lengt

Airida [17]

Answer:

Option (C)

Step-by-step explanation:

In the given circle, AB is a chord passing through the center O.

Therefore,chord AB is a diameter of the circle and OC is the radius.

AO = OB = OC

OC⊥AB, and length of OC = 7 cm

By applying Pythagoras theorem in right ΔBOC,

BC² = OC² + OB²

BC = $\sqrt{OC^{2}+OB^{2}}$

= $\sqrt{7^2+7^2}$

= $7\sqrt{2}$

≈ 9.9 units

Therefore, Option (C) will be the answer.

7 0

3 years ago

Please help work this equation

Flauer [41]

Hi!

<u>Given these two equations:</u>

$x = y + 8$

$x + 4 = 2(y + 4)$

We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:

$(y+8)+4=2(y+4)$

Combine like terms on both sides:

$y+12=2y+8$

Subtract y from both sides:

$12=y+8$

Subtract 8 from both sides:

$y=4$

Now, we can simply plug the y value in to the first equation, and solve for x:

$x=4+8$

Simplify:

$x=12$

<h3>Therefore, x is equal to 12 and y is equal to 4.</h3>

<u>Learn more about the substitution (and also elimination!) method here:</u>

brainly.com/question/14619835

4 0

2 years ago

Solve for − ∣ x − 2 ∣ + 4 ≤ 0

MakcuM [25]

Answer:

x ≥ 6 or x ≤ -2

Step-by-step explanation:

- I x - 2 I + 4 ≤ 0

- I x - 2 I ≤ -4

I x - 2 I ≥ 4

x - 2 ≥ 4 or x - 2 ≤ -4

x ≥ 6 or x ≤ -2

5 0

3 years ago

Rick knows that 1 cup of glue weighs 1/18 pound. He has 2/3 pound of glue. How many cups of glue does he have?

Basile [38]

$\begin{array}{ccc}1\ cup&-&\frac{1}{18}\ lb\ (pound)\\\\x\ cup&-&\frac{2}{3}\ lb\ (pounds)\end{array}\ \ \ \ \ \ cross\ multiply\\\\\\\frac{1}{18}x=1\times\frac{2}{3}\\\\\frac{1}{18}x=\frac{2}{3}\ \ \ \ \ \ |multiply\ both\ sides\ by\ 18\\\\18\times\frac{1}{18}x=18\times\frac{2}{3}\\\\x=6\times2\\\\\boxed{x=12}\\\\Answer:He\ has\ 12\ cups\ of\ glue.$

6 0

3 years ago