If the question is Log4 (8/x)^2
Then...
Log^2 2^2 (8/x)
(1/2 Log2 (8/x))^2
1/4 Log^2 2(8/x)
(log^2 2(8/x))/4
(9-6log2 (x)+ log^2 2(x))/4
to answer on cube root we need to use the prime factorisation.
which means using only prime number and dividing the number by suitable prime number.
after find prime factorisation we know that cube root is 3th power of number.
so if we have same three number we need to take it as one because it is a cube root .
for example![\sqrt[3]{5*5*5} =\sqrt[3]{5^3} =5.](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B5%2A5%2A5%7D%20%3D%5Csqrt%5B3%5D%7B5%5E3%7D%20%3D5.%20)
So you got the answer already
Use slope formula
y^2-y^1/x^2-x^1
the answer is -4/3
<u>Subtracting Fractions with Different Denominators</u>
(Picture Included)
<h2>Answer:</h2><h2><u>-1 </u></h2><h2>
6 </h2><h2 /><h3>
Find the least common denominator</h3>
6 is our least common denominator, so multiply <u>2⋅3=6</u>, and do the same thing to the numerator. <u>1⋅3=3</u>
<u>now, the second fraction. 3⋅2=6</u>
Again, if you multiply from the bottom, do it to the top.
<u>2⋅2=4</u>
<h3>3/6-4/6= -1/6</h3>
(3 - 4 = -1)