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Tju [1.3M]
3 years ago
7

Calcular el área y el perímetro de un círculo que tiene 50 cm de radio

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

Area: 7850 square cm

Perimeter: 314 cm.

Step-by-step explanation:

The area is \pi r^{2}. With r=50, \pi 50^{2}=2500π which is about (2500)(3.14)=7850.

The perimeter is 2\pi r which is the same as (diameter)(π). The diameter is 100, so 100\pi which is about (100)(3.14)=314.

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PLEASE HELP!!!
Oksanka [162]

Answer:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

Step-by-step explanation:

PLEASE HELP!!!

1. Under what conditions must we assume a Student t distribution for the sampling distribution of sample means when testing a claim about a population mean?

2. Give one difference between the Student t distribution and the normal distribution.

3. Which TI-84 calculator command or StatCrunch dialog box is used to find the P-value given a t test statistic?

4 0
3 years ago
the cost of two sound systems were decreased by 10 the orginal cost of the systems were 90 dollars and 60 dollars which had a gr
Alex Ar [27]
I would say 60 cause 10% of 90 is 9 which is a difference of 81 while 10% of 60 is 6 which is a difference of 54. 
3 0
3 years ago
Jeffery conducted a survey in his school and found that 30 of the 50 eighth grade students' favorite subject is mathematics. Bas
Ivahew [28]

The correct answer is:

D) Jeffery's conclusion is not valid because the sample was biased since all of the students were eighth grade students.

3 0
3 years ago
2) The coordinates of the vertices of quadrilateral ABCD are A(-1,8),
Verizon [17]

Answer:

The coordinates of vertices of A'B'C'D' are:

A'(1,-8), B'(0,-4), C'(2,-1) and D'(4,-3)

Step-by-step explanation:

When a point (h,k) is roated 180 degrees about the origin it becomes (-h,-k) which means that the new point after rotation is the negative of the previous.

Given vertices are:

A(-1,8),  B(0,4), C(-2,1), and D(-4,3)

The new vertices will be:

A(-1,8) => A'(1,-8)\\B(0,4)=> B'(0,-4)\\C(-2,1)=> C'(2,-1)\\D(-4,3)=> D'(4,-3)

The coordinates of vertices of A'B'C'D' are:

A'(1,-8), B'(0,-4), C'(2,-1) and D'(4,-3)

3 0
3 years ago
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions
Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector \vec{v} in some vector space \mathbb R^n we have

\vec{v} = \langle a,b\rangle

This is the component form. I don't like that way. It is probably used in high school, but

\vec{v} =  \begin{pmatrix} a\\ b\\ \end{pmatrix}

is preferable because the inner product on \mathbb R^n is defined to be

$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

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4.

For this question, I think you meant

vectors

\vec{u_1} = (-8, 12)

\vec{u_2}  = (13, 15)

Once

\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}

Considering that the dot product is

\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76

and the norm of \vec{u_1} is ||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}

and the norm of \vec{u_2} is ||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}

Thus,

\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}

\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)

3 0
3 years ago
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