All categories

3 years ago

Write an equation and solve

Mathematics

1 answer:

hjlf3 years ago

7 0

Answer:

$10.75

Step-by-step explanation:

41 / 4 = 10.25

71.75 / 7 = 10.25

One ticket would cost $10.75

You might be interested in

What is the measure of EH!?!????? RUNNING OUT OF TIME

vladimir2022 [97]

I think the answer is B.

6 0

3 years ago

2x - 5x = what does it equal Helppppp

erma4kov [3.2K]

Answer:

-3x hope this helps you good luck

6 0

3 years ago

Read 2 more answers

Solve the simultaneous equations: 3x + 2y = 35 2x + 3y = 30

lesya [120]

Answer:

nuber 1

Simplifying

3x + 2y = 35

Solving

3x + 2y = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

3x + 2y + -2y = 35 + -2y

Combine like terms: 2y + -2y = 0

3x + 0 = 35 + -2y

3x = 35 + -2y

Divide each side by '3'.

x = 11.66666667 + -0.6666666667y

Simplifying

x = 11.66666667 + -0.6666666667y

5 0

2 years ago

An express train travels 80km/h from Ironton to Wildwood. A local train, traveling at 48km/h, takes 2 hours longer for the same

masha68 [24]

Answer:

They are 240 kilometers apart.

Step-by-step explanation:

This question can be solved using the following relation:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance and t is the time.

An express train travels 80km/h from Ironton to Wildwood.

Here we have $v = 80, t = x$ . So

$v = \frac{d}{t}$

$80 = \frac{d}{x}$

$d = 80x$

A local train, traveling at 48km/h, takes 2 hours longer for the same trip.

This means that when $v = 48, t = x + 2[tex]. So[tex]v = \frac{d}{t}$

$48 = \frac{d}{x+2}$

Since $d = 80x$

$48 = \frac{80x}{x+2}$

Applying cross multiplication

$80x = 48(x + 2)$

$80x = 48x + 96$

$32x = 96$

$x = \frac{96}{32}$

$x = 3$

So the distance is:

$d = 80x = 80*3 = 240$

They are 240 kilometers apart.

3 0

3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago