This is a geometric sequence because each term is twice the value of the previous term.  So this is what would be called the common ratio, which in this case is 2.  Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1)  so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r)  where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so 
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
        
                    
             
        
        
        
Answer:
y= -4x + 3
Step-by-step explanation:
Because the slope is -4/1 which is the same as 4 and 3 is the y-intercept. 
Here's the work;
 We can just use the first two coordinates which are (0,3) and (1,-1) to get from the x-value 0 to 1 we add 1. and to get from the y-value 3 to -1 we subtract 4. Therefore the slope is -4 and the y- intercept (when x is zero) is 3. Pop that into slope intercept form to get y=-4x +3
Hope that helps and have a great day!
 
        
             
        
        
        
Answer:
30% students
Step-by-step explanation:
Let x be the number of total students of a school.
63% are girls then total number of girls = (0.63)x
37% are boys then total number of boys = ( 0.37)x
Now 23% of girls wear contacts then total number of girls 
= (0.63x) × 0.23
=  (0.1449x)
And 42% of boys wear contacts then total number of boys wearing contacts
= (0.37x) ( 0.42)
= (0.1554)x
Total students wears contacts = ( 0.1449x) + (0.1554x)
                                                   = (0.3003x)
Percentage of students wear contacts =  × 100
 × 100
 =  × 100
 × 100
= 30%
All 30% students wear contacts.
 
        
             
        
        
        
Subtract 12x from 84x = 72x
        
                    
             
        
        
        
Um what alcan u finish the question xD