Given:
Quadrilateral PQRS
P(o, o), Q(a+c, o), R(2a+c, b), S(a, b)
Find:
whether the diagonals are perpendicular using coordinate geometry
Solution:
If the diagonals are perpendicular, their slopes multiply to give -1.
The slope of PR is
(b-o)/(2a+c-o)
The slope of QS is
(b-o)/(a-(a+c)) = (b-o)/(-c)
The product of these slopes is
(b-o)·(b-o)/((2a+c-o)(-c))
This value will not be -1 except for very specific values of a, b, c, and o.
It cannot be concluded that the diagonals of PQRS are perpendicular based on the given coordinates.
Answer:
x= 8
Step-by-step explanation:
Step 1- Distribute into the parenthesis by 1.
4x+2+3(-1)+3(-1)x= 7
Step 2- Simplify.
4x+2-3-3x= 7
Step 3- Add common variables.
(4x-3x)+(2-3)
1x-1= 7
Step 4- Add 1 to both sides.
1x-1= 7
+1 +1
1x= 8
Step 5- Divide both sides by 1.
1x= 8
1 1
x= 8
Can you give me a Brainliest
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Answer:
your answer would be b
Step-by-step explanation:
got it right
