<u>Answer:</u> The initial molarity of cation is 2.38 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of = 46.3 g
Molar mass of = 129.6 g/mol
Volume of solution = 150 mL
Putting values in above equation, we get:
1 mole of produces 1 mole of cation and 1 mole of anion
So, molarity of cation = (1 × 2.38) = 2.38 M
Hence, the initial molarity of cation is 2.38 M
Answer:
1.) 2 molecules
2.) 4 H atoms, 2 S atoms, 2 O atoms
3.) 8 total atoms
Explanation:
1.) 2 H₂SO
--------> The molecule is all of the elements bonded together (H₂SO). Because there is a coefficient of 2 in front of the molecule, this means that there are 2 molecules present.
2.) 2 H₂S₁O₁
---------> The number of atoms of each element is determined by the subscripts and the coefficients. In one molecule, there is one oxygen, one sulfur, and 2 hydrogen atoms (denoted by subscripts). Because there are two molecules, these values are doubled.
3.)
--------> The total number of atoms is calculated by adding the number of atoms of each element. If between 2 molecules there are 4 hydrogens, 2 sulfurs, and 2 oxygens, combined there would be a total of 8 atoms.
is the a waited for me to help you
Answer:
Multiply 1.25 by 0.04 and divide the result obtained by 1,000
Explanation:
Given: [1 gram = 0.04 ounce, 1 liter = 1,000 milliliter]
1.25 x 0.04 = 0.05 oz
Therefore, 0.05 per 1,000 milliliter
0.05 ÷ 1,000 = 0.00005 oz
Therefore, the density of the gas is 0.00005 oz/mL
Hope this helps! :)