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Schach [20]
4 years ago
7

What is 62,810 rounded to the nearest

Mathematics
1 answer:
sweet-ann [11.9K]4 years ago
3 0
62,810 rounded up is 60,00
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In isosceles triangle the length of the base is twice shorter than the length of a leg. The perimeter of this triangle is 50 cm.
andrew11 [14]

The length of the base is 10 and the length of each leg is 20.

In order to find this, we can start by making the length of the base x. Now we know that the legs are twice as long, which would make them 2x. Since there are two of them, we can add x + 2x + 2x and set equal to 50 to find the value of x.

x + 2x + 2x = 50

5x = 50

x = 10

Now we can plug this in for our leg length as well to find that.

2x = Leg

2(10) = Leg

20 = leg

4 0
3 years ago
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An extended ratio compares three or more numbers. In the extended ratio a:b:c, we have the ratio A:b,c and a:c
Liono4ka [1.6K]

Answer:

see the explanation

Step-by-step explanation:

we know that

An extended ratio compares three or more numbers.

In the extended ratio a:b:c

The ratio of the first two numbers is a:b (you can write a to b or a/b)

The ratio of the last two numbers is b:c (you can write b to c or b/c)

The ratio of the first and last numbers are a:c  (you can write a to c or a/c)

6 0
3 years ago
Pre Calculus
attashe74 [19]

x² + 2x + 2

Step-by-step explanation:

(F + G)(x)

= F(x) + G(x)

= 2x + x² + 2

= x² + 2x + 2

7 0
3 years ago
Colby baked 14 cookies on Saturday. On both Saturday and Sunday, he baked a total of 36 cookies. Which of the following equation
alisha [4.7K]

Answer:

d

Step-by-step explanation:

what he baked on saturday plus what he baked on sunday equals what he baked in all

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3 years ago
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Sin(-180° + θ) = ________
Svet_ta [14]

Answer:

\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)

Step-by-step explanation:

We need to find the value of \sin(-180^o+ \theta)

So let's apply formula

\sin\left(A+B\right)=\sin\left(A\right)\cos\left(B\right)+\sin\left(B\right)\cos\left(A\right)

\sin\left(-180^o+\theta\right)=\sin\left(-180^o\right)\cos\left(\theta\right)+\sin\left(\theta\right)\cos\left(-180^o\right)

\sin\left(-180^o+\theta\right)=0\cdot\cos\left(\theta\right)+\sin\left(\theta\right)\cdot\left(-1\right)

\sin\left(-180^o+\theta\right)=0-\sin\left(\theta\right)

\sin\left(-180^o+\theta\right)=-\sin\left(\theta\right)

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