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Schach [20]
3 years ago
7

What is 62,810 rounded to the nearest

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0
62,810 rounded up is 60,00
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HELP PLEASE!!
zhenek [66]

Answer:

y = 1/2x + 1.

Step-by-step explanation:

Use the point-slope form of a straight line:

y - y1 = m(x - x1)     (where m=slope and(x1,y1) is a point on line).

y - 3 = 1/2(x - 4)

y = 1/2x - 2 + 3

y = 1/2x + 1.

7 0
3 years ago
Write as a decimal 23/9
Slav-nsk [51]

Answer:

2.555555555555.....

(the 5 is repeating)

Step-by-step explanation:

This is the answer because:

1) To convert the fraction to a decimal, you have to divide the numerator by the denominator.

2) Therefore, 23/9 is 2.5 (the 5 is repeating)

Hope this helps!

8 0
3 years ago
Find the surface area of the cube shown below. units 2 2 squared
ruslelena [56]

The surface area of the cube with a side length of 2 units is 24 units squared

<h3>How to determine the surface area?</h3>

The side length of the cube is given as:

l = 2

The surface area is calculated as:

Surface area = 6l^2

This gives

Surface area = 6 *2^2

Evaluate

Surface area = 24

Hence, the surface area of the cube is 24 unit squared

Read more about surface area at:

brainly.com/question/13175744

#SPJ1

7 0
2 years ago
Choose = , &lt; , or &gt; so that each statement is true. When x = 0, y1 y2 When x = 5, y2 y3 Choose y1, y2, and y3 so that the
serg [7]
< because you wouldnt need >
3 0
3 years ago
Simplify. (Assume all variables represent positive real numbers). Leave answer in radical form.
Flauer [41]

Answer:

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64 * 2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{13}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{3} * b^{6} * \sqrt{b}

Rewrite as:

\sqrt{128a^{6}b^{13}} = 8 * a^{3} * b^{6}* \sqrt{2}  * \sqrt{b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

5 0
3 years ago
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