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padilas [110]
3 years ago
14

45. A 30°-60°-90° triangle has a hyp 30 meters. Find the length of its

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0
Really u don’t know by now
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Step-by-step explanation:

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HELP ME PLEASE!!!!
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54=9\cdot6\\24=4\cdot6\\\\3\sqrt{54}-4\sqrt{24}=3\sqrt{9\cdot6}-4\sqrt{4\cdot6}=3\cdot\sqrt9\cdot\sqrt6-4\cdot\sqrt4\cdot\sqrt6\\\\=3\cdot3\cdot\sqrt6-4\cdot2\cdot\sqrt6=9\sqrt6-8\sqrt6=1\sqrt6=\sqrt6\\\\\text{Answer:}\ \sqrt6\\\\\text{Used:}\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}
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Classify the following expression by degree and term: x2y − 7xy + xyz + x
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3rd degree polynomial with 4 terms
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Julie gives 7 pieces of candy to each of her friends. If Julie gives all of her candy away, which amount of candy could have bee
True [87]
To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.

161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857

Obviously, Julie cannot give a fraction of an amount of candy to someone.  So that rules out that she had 162, 145, or 128 pieces of candy.  

The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
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3 years ago
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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)
lisov135 [29]

Answer:

(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

Step-by-step explanation:

(a) To find the solutions of the following system of equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. you must:

Multiply 2x-3y=3 by 2:

\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}

Subtract the equations

4x-6y=3\\-\\4x-6y=6\\------\\0=-3

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. you must:

Isolate x for 4x-6y=10

x=\frac{5+3y}{2}

Substitute x=\frac{5+3y}{2} into the second equation

16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40

The system has many solutions.

Isolate y for 4x-6y=10

y=\frac{2x}{3}-\frac{5}{3}

3 0
3 years ago
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