Question

a pebble fall into a pond from the surface sealevel it descends at a rate of 2feet per second where is the pebble in relation to the surface of the pond after 5 second

Answer 1

Pebble falls into the pond from the surface and it descends at a rate of 2 feet per second.

So basically, the pebble is descending or falling down at 2 feet per second which means after every 1 second, it goes 2 feet down.

The equation to represent the depth of the pebble with time is given by:

$d= 2 \times t$

Where, 'd' is the depth after certain time and 't' is the time in seconds.

Now, we need to find the depth of the pebble after 5 seconds.

Plugging the value $t=5$, we get:

$d=2\times 5=10 ft$

So, after 5 seconds the pebble will be at the depth of 10 feet.