Answer:
log(x^7·y^2)
Step-by-step explanation:
The applicable rules are ...
... log(a^b) = b·log(a)
... log(ab) = log(a) +log(b)
_____
The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.
The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.
Now, you have the sum ...
... log(x^7) +log(y^2)
The second rule tells you this can be rewritten as ...
... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection
Step-by-step explanation:
let the big cube side be b
small cube side be s
s = 2/3 * b
bv + sv = 118.125
b^3 + 8/9 b^3= 118.125
17 b^3/8 = 118.125
b^3 = 55.58
b = 3.816in
s = 2.544in
Answer:
6.79
Step-by-step explanation:
First of all, you will have to know how much is 3% of 7 in order to decrease it by that amount.
7 x 0.03 = 0.21
Now that you know the amount, you can subtract it from seven and therefore you have decreased 7 by 3%.
7 - 0.21 = 6.79
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