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Harrizon [31]
3 years ago
7

In the figure, segment RD bisect segment DE at S. Given that DS=4x+12 and SE=8x-8, find the value of x.

Mathematics
1 answer:
Triss [41]3 years ago
4 0

Answer:

x = 5

Step-by-step explanation:

DS = 4x + 12

SE = 8x - 8

Since segment RS bisects segment DE, it implies that the two segments created, segments DS and SE, are congruent. Therefore:

4x + 12 = 8x - 8

Solve for x

4x + 12 - 8x = 8x - 8 - 8x (Subtraction property of equality)

-4x + 12 = - 8

-4x + 12 - 12 = - 8 - 12 (subtraction property of equality)

-4x = - 20

\frac{-4x}{-4} = \frac{-20}{-4}

x = 5

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Step-by-step explanation:

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brainliest if correct

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