Question

In the figure, segment RD bisect segment DE at S. Given that DS=4x+12 and SE=8x-8, find the value of x.

Answer 1

Answer:

$x = 5$

Step-by-step explanation:

DS = 4x + 12

SE = 8x - 8

Since segment RS bisects segment DE, it implies that the two segments created, segments DS and SE, are congruent. Therefore:

$4x + 12 = 8x - 8$

Solve for x

$4x + 12 - 8x = 8x - 8 - 8x$ (Subtraction property of equality)

$-4x + 12 = - 8$

$-4x + 12 - 12 = - 8 - 12$ (subtraction property of equality)

$-4x = - 20$

$\frac{-4x}{-4} = \frac{-20}{-4}$

$x = 5$