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3 years ago

At top speed, a boat can cover 1,533 kilometers in 3 hours what unit rate does the boat travel during this time frame?

Mathematics

1 answer:

svlad2 [7]3 years ago

4 0

The unit rate that the boat can travel during this time frame is 511 kilometers in 1 hour.

Hope this helped ((:

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How do I solve for x

Alchen [17]

Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
$a^2+b^2=c^2$

Input the information from the diagram into the formula:
$(x)^2+(x+7)^2=(13)^2$

Expand each term:
$(x)^2+(x+7)^2=(13)^2$

$x^2+((x+7)(x+7))=169$

$x^2+(x(x+7)+7(x+7))=169$

$x^2+x^2+7x+7x+49=169$

Combine like terms:
$2x^2+14x+49=169$

Add -169 to both sides:
$(2x^2+14x+49)+(-169)=(169)+(-169)$

$2x^2+14x-120=0$

Factor out the Common Term (2):
$2(x^2+7x-60)=0$

Factor the Complex Trinomial:
$2(x^2-5x+12x-60)=0$

$2(x(x-5)+12(x-5))=0$

$2(x-5)(x+12)=0$

Set Factors to equal 0:
$x-5=0$

$x=5$

or

$x+12=0$

$x=-12$

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is:
$\boxed{x=5}$

I hope this helped!
-Benjamin

6 0

3 years ago

Using the image prove its shape.

Vladimir79 [104]

The shape is a parallelogram because the length of the sides based on the coordinates

5 0

3 years ago

Convert: 106 mi = ________ km

Bond [772]

1 km=0.621mi
xkm=106 mi
x=106/0.621=170.66
b is the answer

6 0

4 years ago

Read 2 more answers

Combine the like terms to create an equivalent expression:<br>4z-(-3z)

Verdich [7]

the answer is 12z²

Step-by-step explanation:

u just multiply the 4z-(-3z).

7 0

3 years ago

I’m confused and don’t have an angle tool to even try to do the question

yanalaym [24]

<h3>Answer: 40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0

3 years ago