What this setup essentially represents is “How many 8s can we take away from 32 before hitting 0?” Which in turn can be reframed as “How many 8s fit into 32?” This can be captured in the expression 32 / 8. As we can see from the problem, we can take away 4 8’s before hitting 0, so that gives us the equation 32 / 8 = 4
Answer:
I think the answer is c - $ 55,000
Step-by-step explanation:
Answer:
11/15
Step-by-step explanation:
22/30 = 11/15 because they both have a common factor of 2 in the numerator and denominator.