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nevsk [136]
2 years ago
9

Lucas read 30% of his book n

Mathematics
1 answer:
maw [93]2 years ago
3 0

Answer:

WHAT IS THE question


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Find x.______________a0
velikii [3]

Answer:

x=4

Step-by-step explanation:

Before we find x, we need to set up this triangle a little more. We need to find the triangle's altitude before we can solve for x. We will use the heartbeat method to find the altitude.

Let altitude = y; solve for y:

\frac{2}{y}=\frac{y}{6}

y^2=12

y=\sqrt{12}

y=2\sqrt{3}

Now that we know the altitude, we can use the Pythagorean Theorem to find the hypotenuse (x).

a^2+b^2=c^2

2^2+(2\sqrt{3})^2=c^2

4+12=c^2

c^2=16

c=4

Since c and x are the same; c is just the hypotenuse in the Pythagorean Theorem.

x=4

4 0
3 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
2 years ago
A seamstress has 1/4 of a foot of thread. Then she uses 1/5 of a foot of thread to sew a hole. How much of the thread is left?
Ilya [14]
Answer is <span>C) 1/20 of a foot

1/4 -1/5
= 5/20 - 4/20
=1/20</span>
3 0
3 years ago
HELPPPPPPPPPPPPPPPPPP
ANEK [815]

Answer:

23 or 22....

Step-by-step explanation:

because he got 3 questions wrong sooooo yeah... ya✋

3 0
2 years ago
Read 2 more answers
after 3/4 of a minute a sloth has moved just 3/8 of a foot. what is the sloths speed in feet per minute
grigory [225]
 I think this is how you do it: You would multiply 3/8 to 3/4 min...then convert into decimal..and get 0.5 min.
5 0
2 years ago
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