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3 years ago

PLZ ONLY TYPE IN SSS , ASA, SAS, AAS, HL) IF the triangles are not congruent, type in NEI

Mathematics

1 answer:

hichkok12 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

the first picture shows that two sides are the same and one angle so you know it's a SAS, the one tick mark and that the two trialge share one common side is how you know 2 sides are the same, and the 90 ° corner symbol shows you know an angle in each , that is also the same.

the second picture shows 3 sides the same so SSS, the triangles share one side, and have the tick marks, showing that each of the respective sides are the same.

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Help again! Just these last 3 questions. I don't wanna beg for answers, but I need help thank you. This assis due in a few minut

lana [24]

Answer:

Question 4: 20 + 6 + 6 + 12 + 16 = 60 $yd^{2}$

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Step-by-step explanation:

Hope this helps!

6 0

3 years ago

PLEASE HELP QUICKLY!!! There is a tree standing in the desert; the sun is rising to the east.

a_sh-v [17]

A. As sun peeks, it creates a straight line- sun to tree to shadow, angle=180°
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3 years ago

PLZZ HELP!!!! ASAP PLZ!!!! XTRA POINTS!!!

schepotkina [342]

Answer:

38.1 cm²

Step-by-step explanation:

area of full circle = π6² = 113.04 cm²

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3 0

3 years ago

Find the equation of a line that has a slope of 1/2 and passes through the origin.

omeli [17]

Step-by-step explanation:

The equation of a line with slope m and y-intercept b is y = m x + b.

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3 years ago

The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to

Firdavs [7]

Rewrite the boundary lines y = -1 - x and y = x - 1 as functions of y :

y = -1 - x ==> x = -1 - y

y = x - 1 ==> x = 1 + y

So if we let x range between these two lines, we need to let y vary between the point where these lines intersect, and the line y = 1.

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$\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy$

The integral with respect to x is trivial:

$\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy$

For the remaining integral, integrate term-by-term to get

$\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}$

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line y = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

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3 years ago