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zysi [14]
3 years ago
6

Multiply: -12y(y - 6) Enter the correct answer. ​

Mathematics
2 answers:
Ahat [919]3 years ago
6 0
Expand the brackets :
(-12y x y) -(-12y x -6)

= 12y^2 +72y
bogdanovich [222]3 years ago
3 0

Answer:

-13y - (-72y)

59y is answer

Step-by-step explanation:

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Compare. Write &lt;, &gt;, or=.<br>11. V8 +3( ) 8+ V3​
Levart [38]

Answer:

=

Step-by-step explanation:

v8 + 3 = 8 + v3

-3 -3

________________

v8 = 5 + v3

-v3 -v3

___________

v5 = 5

8 0
3 years ago
Can someone help me with this math homework please!
alisha [4.7K]

Answer:

X1 = 2 Y1 = -5

Step-by-step explanation:

math simple slope

5 0
3 years ago
What is the equation of a line parallel to y=7x-8 that passes through (5,-2)
Wewaii [24]

Answer:

y=7x+8

Step-by-step explanation:

Find the slope of the original line and use the slope-intercept form


7 0
3 years ago
A student took a total of 4 tests over the course of 8 weeks. How many weeks of school will the student attend to take a total o
Julli [10]

Answer:

4/8 = 20/x

20 x 8 = 160

160 ÷ 4 = 40

the student will attend 40 weeks of school

3 0
2 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
2 years ago
Read 2 more answers
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