The Oxidation-Fermentation Test is used to differentiate bacteria built on their capability to oxidize or ferment specific sugars.
Once microbes are inoculated,-One tube is sealed with a layer of sterile mineral oil to promote anaerobic growth and fermentation.-The other tube is left unsealed to allow aerobic growth and oxidation.
Organisms able to ferment the carbohydrate or ferment and oxidize the carbohydrate will turn the sealed and unsealed yellow throughout.
Organisms able only to oxidize the sugar will turn the unsealed yellow medium and leave the sealed medium green or blue.
Fragile fermenters will convert both tubes slightly yellow at the top.
Organisms not able to metabolize the sugar will either produce no color change or will turn the medium blue due to alkaline products from amino acids degradation.
Since Pair #1 showed complete yellowing for sealed and unsealed, these Organisms able to ferment the carbohydrate or ferment and oxidize the carbohydrate. So our interpretation will be that the organism has: Oxidation and fermentation OR fermentation only.
For tubes #2 and #3, the sealed tubes were green throughout suggests that they need oxygen for aerobic growth, and the fact that their unsealed tubes showed light yellowing is evidence for oxidation. Sealed - Green and Unseal - Yellow. Our interpretation for these pairs of tubes would be : Oxidation
Tube 1 can be either Oxidation and fermentation OR fermentation only. So reliability of this needs to be confirmed more with additional testing.
Tubes 2 and 3 are most reliable because they can only be oxidation only and no fermentation.
<h3><u>Answer;</u></h3>
Lithosphere
<h3><u>Explanation</u>;</h3>
- Lithosphere is the solid outer part of the earth which includes the brittle upper portion of the crust and the mantle. It is bounded by the asthenosphere below and the atmosphere above.
- <em><u>The pressure in the lithosphere is about 109 gigapascals or GPa. </u></em>
- <em><u>Asthenosphere has a pressure of about 18 GPa</u></em>
- <em><u>The mantle is a layer between the outer core and the crust, it has a pressure of about 149 GPa.</u></em>
Answer:b
Explanation:
It will only be found in some cells because when a mutation is formed it will most likely not be able to spread
Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
Answer:
a) Yes
b) Yes
c) Yes
d) Yes
Explanation:
a.
In the exons?
Yes mutant site will be expected. It will transcript-ed as well and it can be a polypeptide depending on the mutation type.
b.
In the intron?
Yes mutant site will be expected. It will be transcript-ed as well and it cannot be a polypeptide
c.
In the promoter?
Yes mutant site will be expected. It will not be transcript-ed and it cannot be a polypeptide
d.
In the intron-exon boundary?
Yes mutant site will be expected. It will be transcript-ed and it cannot be a polypeptide
