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nydimaria [60]
3 years ago
9

Question 5 (Multiple Choice Worth 4 points)

Mathematics
2 answers:
loris [4]3 years ago
7 0
(-2,2) (0,1)
slope = y1-y2/x1-x2 .... 2-1/-2-0 = -1/2 the answer is C
Nitella [24]3 years ago
3 0

Answer:  \dfrac{-1}{2} or -1 over 2.

Step-by-step explanation:

The slope of a line passing through points (a,b) and (c,d) is given by :-

m=\dfrac{d-b}{c-a}

From the given graph , the line is passing from points (-2,2) and (0,1).

Now, the of a line passing through points (-2,2) and (0,1) is given by :-

m=\dfrac{1-2}{0-(-2)}\\\\\Rightarrow\ m=\dfrac{-1}{2}

Hence, the slope of the line = \dfrac{-1}{2}

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Solve this systems of equation word problem. please
agasfer [191]
2b+h = 4.82
b+2h = 3.70
multiply the second equation by 2:
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subtract the first equation from it:
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3 years ago
Unit 5: Systems of Equations & Inequalities Homework 2: Solving Systems by Substitution
Oksanka [162]

By solving the system by substitution, we got the solutions:

x = 2/3, y = 8/3.

<h3>Solving the system of equations:</h3>

I guess we need to solve problem number 5, so let's do that.

Here we have the system of equations:

y = x + 2

3x + 3y = 6

To solve it by substitution, we need to isolate one of the variables in one of the equations and then replace that in the other equation.

For example, here we can see that "y" is already isolated in the first equation, so we can use that and replace it in the second equation.

3x + 3y = 6

3x + 3*(y = x + 2) = 6

3x + 3*(x + 2) = 6

Now we have an equation that only depends on x, so we can solve it:

3x + 3x + 2 = 6

6x + 2 = 6

6x = 6 - 2 = 4

x = 4/6 = 2/3.

Now we can use the first equation to find the value of y:

y = x + 2 = 2/3 + 2 = 2/3 + 6/3 = 8/3.

Then the solution is:

x = 2/3 and y = 8/3.

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

6 0
3 years ago
Draw graphs of the following lines: The line through (-5, 2) having the slope of -3
Ivanshal [37]
What you want to do here is take this information and plug it into point-slope form. any time you're given a point and a slope, you generally want to plug it into this equation: y - y1 = m(x - x1).

in this equation, m is your slope and (x1, y1) is a given point. plug in your info--slope of -3 and (-5, 2).

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that is the equation of your line. however, if you want to graph it, this doesn't really make much sense to you. convert it to slope-intercept form, y = mx + b, by solving for y.

y - 2 = -3(x + 5) ... distribute -3
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after you've plotted that point, you use your slope to graph more. remember that your slope is "rise over run"--you rise up/go down however many units, you run left/right however many units. if your slope is -3, you want to go down 3 units, then go to the right 1 unit. remember that whole numbers have a 1 beneath them as a fraction. -3/1 is your rise over 1.
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