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Xelga [282]
3 years ago
11

How many centimeters are equal to 2 kilometers?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
3 0
1km=1000m
1m=100cm
so:
2km=2*1000m=2*1000*100cm=200000cm
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Can someone plsss help :)
OLga [1]
Set equal to eachother
(2x+1) = 79
Subtract 1 from both sides
2x=78
Divide 2 from both sides
2x/2=78/2
X= 39
5 0
3 years ago
3.Write the product as a trinomial. (2r – 5)(r + 10)
Maurinko [17]
B is the correct answer

5 0
2 years ago
Read 2 more answers
Gail has eight united states coins. Their total value is 93 cents. What coins does she have?
Kryger [21]
8 coins = $0.93

3 quarters = $0.75
1 dime = $0.10
1 nickel = $0.05
3 pennies = $0.03

3 + 1 + 1 + 3 = 8 coins

$0.75 + $0.10 + $0.05 + $0.03 = $0.93

5 0
3 years ago
Question 6 (2 points)
irinina [24]

to inverse a equation make all y's x and andy x's y

Thus the inverse is

x=4y-8

Evaluated to

4y=x+8

y=

3 0
2 years ago
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
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