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3 years ago

13

58 = 7/4x well, basically I am really bad with fractions, and I'm supposed to do this on a computer, I don't have a calculator I

understand, please help.

1 answer:

KiRa [710]3 years ago

4 0

58=7/4x
Multiply both sides by 4 so the fraction cancels out:
232=7x
Divide both sides by 7:
x=33.14 (rounded)

Hope this helps :)

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Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

3 years ago

the function 56-4y=-5x can be used to determine the total amount of money in a coin jar,y,after money is added for x days. what

notka56 [123]

Answer:

23

Step-by-step explanation:

4 0

3 years ago

What is the square root of 55

nikitadnepr [17]

$\sqrt{55 } = 7.41.....$
It is non recurring number

Hope it helps you

3 0

4 years ago

I need help please i am so bad at math

Citrus2011 [14]

Answer:

Um I might be able to help depending on what type of math it is.

5 0

3 years ago

How do you convert 60 miles per hour is how many feet per second? can iny one help

DiKsa [7]

That's two questions.

The answer to the second question is: Yes.

The answer to the first question is:

Multiply 60 miles per hour by ' 1 ' a few times. Use fractions that have
the same thing on top and bottom, since those are always equal to ' 1 '.
Then cancel units if the same unit is on the top and the bottom.
Here's how it goes:

(60 mi/hr) x (5280 ft/mile) x (1hr/3600 sec) = (60 x 5280 / 3600) ft/sec = <u>88 ft/sec</u>

8 0

3 years ago