Answer:
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suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
The 12 ounce bottle is a better buy as the customer spends less per ounce ($0.1158/oz) than the 24 ounce ($0.1163/oz).
Answer:
14+5 = 19
19 + 15/2
15/2 = 7.5
19+7.5 = 26.5
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Step-by-step explanation: