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3 years ago

Thank you so much if so

Mathematics

2 answers:

rosijanka [135]3 years ago

4 0

Answer:

Yall need to stop w/ this ¨drop your social¨

Step-by-step explanation:

Alex73 [517]3 years ago

4 0

Answer:

Mathaway, Symbolab, etc.

Step-by-step explanation:

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The nth term of a sequence is 3n + 2

gavmur [86]

Answer:

see explanation

Step-by-step explanation:

To calculate the first 3 terms substitute n = 1, 2, 3 into the n th term rule

$a_{1}$ = (3 × 1) + 2 = 3 + 2 = 5

$a_{2}$ = (3 × 2) + 2 = 6 + 2 = 8

$a_{3}$ = (3 × 3) + 2 = 9 + 2 = 11

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substitute n = 10 into the n th term rule

$a_{10}$ = (3 × 10) + 2 = 30 + 2 = 32

3 0

4 years ago

Read 2 more answers

Round 46 7/16" to the nearest 16th inch

mina [271]

46 7/16 is already to the nearest 16th, you are done

3 0

3 years ago

please help.....................................................................................................................

vitfil [10]

The range for group 2 is greater than the range for group 1

8 0

3 years ago

Solve the system and give your answer as a coordinate point in the form (k, c) k+c=100 51k+11c=2500

Aleks [24]

Answer:

k = 35, c = 65

Step-by-step explanation:

Solve the following system:

{c + k = 100 | (equation 1)

{11 c + 51 k = 2500 | (equation 2)

Swap equation 1 with equation 2:

{11 c + 51 k = 2500 | (equation 1)

{c + k = 100 | (equation 2)

Subtract 1/11 × (equation 1) from equation 2:

{11 c + 51 k = 2500 | (equation 1)

{0 c - (40 k)/11 = -1400/11 | (equation 2)

Multiply equation 2 by -11/40:

{11 c + 51 k = 2500 | (equation 1)

{0 c+k = 35 | (equation 2)

Subtract 51 × (equation 2) from equation 1:

{11 c+0 k = 715 | (equation 1)

{0 c+k = 35 | (equation 2)

Divide equation 1 by 11:

{c+0 k = 65 | (equation 1)

{0 c+k = 35 | (equation 2)

Collect results:

Answer: {c = 65 , k = 35

5 0

3 years ago

Jeff has a box containing 26 tiles, each with a different letter of the alphabet. he randomly draws 4 letters, one at a time wit

MArishka [77]

The probability to choose letter n is $\frac{1}{26}$ . After drawing letter n there left 25 letters and the probability to choose the letter w is $\frac{1}{25}$ . After drawing two letters n and w there left 24 letters and then the probability to choose letter b is $\frac{1}{24}$ . After drawing three letters n, w and b there left 23 letters, so the probability to choose letter t is $\frac{1}{23}$ .
Using the product rule for probabilities, you can obtain that $P= \frac{1}{26} * \frac{1}{25} * \frac{1}{24}* \frac{1}{23} =0.0000027$ .

8 0

3 years ago