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VikaD [51]
2 years ago
9

Thank you so much if so

Mathematics
2 answers:
rosijanka [135]2 years ago
4 0

Answer:

Yall need to stop w/ this ¨drop your social¨

Step-by-step explanation:

Alex73 [517]2 years ago
4 0

Answer:

Mathaway, Symbolab, etc.

Step-by-step explanation:

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A. 4 packs of pencils and 3 packs of erasers B. 4 packs of pencils and 5 packs of erasers C. 5 packs of pencils and 3 packs of e
amid [387]
C. 5 packs of pencils and 3 packs of erasers. it is c because no matter what 20(the pack of erasers) is multiplied by it will always end in a zero, therefore you would have to multiply 12 by a number that would make it a multiple of 20 as well which happens to be 5. 5×12=60 and 3×20=60
3 0
3 years ago
Someone please help me out:(
gogolik [260]
SAS mmmmmmmmmmmmmmmmmmm
5 0
2 years ago
Find the integral using substitution or a formula.
Nadusha1986 [10]
\rm \int \dfrac{x^2+7}{x^2+2x+5}~dx

Derivative of the denominator:
\rm (x^2+2x+5)'=2x+2

Hmm our numerator is 2x+7. Ok this let's us know that a simple u-substitution is NOT going to work. But let's apply some clever Algebra to the numerator splitting it up into two separate fractions. Split the +7 into +2 and +5.

\rm \int \dfrac{x^2+2+5}{x^2+2x+5}~dx

and then split the fraction,

\rm \int \dfrac{x^2+2}{x^2+2x+5}~dx+\int\dfrac{5}{x^2+2x+5}~dx

Based on our previous test, we know that a simple substitution will work for the first integral: \rm \quad u=x^2+2x+5\qquad\to\qquad du=2x+2~dx

So the first integral changes,

\rm \int \dfrac{1}{u}~du+\int\dfrac{5}{x^2+2x+5}~dx

integrating to a log,

\rm ln|x^2+2x+5|+\int\dfrac{5}{x^2+2x+5}~dx

Other one is a little tricky. We'll need to complete the square on the denominator. After that it will look very similar to our arctangent integral so perhaps we can just match it up to the identity.

\rm x^2+2x+5=(x^2+2x+1)+4=(x+1)^2+2^2

So we have this going on,

\rm ln|x^2+2x+5|+\int\dfrac{5}{(x+1)^2+2^2}~dx

Let's factor the 5 out of the intergral,
and the 4 from the denominator,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\frac{(x+1)^2}{2^2}+1}~dx

Bringing all that stuff together as a single square,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(\dfrac{x+1}{2}\right)^2+1}~dx

Making the substitution: \rm \quad u=\dfrac{x+1}{2}\qquad\to\qquad 2du=dx

giving us,

\rm ln|x^2+2x+5|+\frac54\int\dfrac{1}{\left(u\right)^2+1}~2du

simplying a lil bit,

\rm ln|x^2+2x+5|+\frac52\int\dfrac{1}{u^2+1}~du

and hopefully from this point you recognize your arctangent integral,

\rm ln|x^2+2x+5|+\frac52arctan(u)

undo your substitution as a final step,
and include a constant of integration,

\rm ln|x^2+2x+5|+\frac52arctan\left(\frac{x+1}{2}\right)+c

Hope that helps!
Lemme know if any steps were too confusing.

8 0
3 years ago
14 - (17 - 5) + 8 <br>I keep getting the wrong answer please help
Furkat [3]

Answer:

The answer is 10

Step-by-step explanation:

  1. 14 -(17 - 5) + 8
  2. 14 -17 + 5 + 8
  3. -3 + 13 = 10
  4. 10 is your answer.
4 0
3 years ago
Mrs. Montgomery earns a 6.5% commission on her total sales. Last month, she had sales of $55,780.
jok3333 [9.3K]

Answer:

Commission: $3625.70

Total (sales + commission): $59405.70

Step-by-step explanation:

6.5% of 55780 = 0.065 × 55780 = 3625.7

55780 increase 6.5% =

55780 × (1 + 6.5%) = 55780 × (1 + 0.065) = 59405.7

7 0
3 years ago
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