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3 years ago

PLEASE HELP!

Mathematics

1 answer:

Arisa [49]3 years ago

7 0

Answer: it turned 115.8°

Step-by-step explanation:

The triangle formed is shown in the attached photo. The angle turned by the ship in the north west direction is ange A. To determine angle A, we would apply the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and A is the angle corresponding to a. Likening the expression to the given triangle, it becomes

165² = 111² + 83² - 2(111 × 83)CosA

27225 = 12321 + 6889 - 2(9213)CosA

27225 = 19210 - 18426CosA

18426CosA = 19210 - 27225

18426CosA = - 8015

CosA = - 8015/18426

CosA = - 0.435

A = Cos^- 1(- 0.435)

A = 115.8° to the nearest tenth

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27 divided by 53 minus 6 plus 53 times -2 squared

mamaluj [8]

Answer:

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Step-by-step explanation:

Considering the expression

27 divided by 53 minus 6 plus 53 times -2 squared

Which can be written as

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

So, solving the expression

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\cdot \left(-\left(2^2\right)\right)\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{27}{53}-6-53\cdot \:2^2$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:6=\frac{6\cdot \:53}{53}$

$=-\frac{6\cdot \:53}{53}+\frac{27}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-6\cdot \:53+27}{53}$

$=\frac{-291}{53}$ ∵ $-6\cdot \:53+27=-291$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-2^2\cdot \:53-\frac{291}{53}$

$=-212-\frac{291}{53}$ ∵ $53\cdot \:2^2=212$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:212=\frac{212\cdot \:53}{53}$

$=-\frac{212\cdot \:53}{53}-\frac{291}{53}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-212\cdot \:53-291}{53}$

$=\frac{-11527}{53}$ ∵ $-212\cdot \:53-291=-11527$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{11527}{53}$

Therefore,

$\left(\left(\frac{27}{53}\right)-6\right)+\left(53\left(-\left(2^2\right)\right)\right)=-\frac{11527}{53}\quad \left(\mathrm{Decimal:\quad }\:-217.49056\dots \right)$

Keywords: algebraic expression

Learn more about solving algebraic expression from brainly.com/question/4687406

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In Evans history class, 10 out of 100 key terms will be randomly selected to appear on the final exam; Evan must then choose 7 o

motikmotik

Answer:

(a) Hypergeometric distribution

(b) 0.785384...

Step-by-step explanation:

(a) looking at the question, we see that $X = \in \{0, ... , 10 \}$ , suppose Evans studied s key terms, this implies that he has not studied 100 - s key terms. Suppose $k = \in \{0, ... , 10 \}$ if X = k, then k out of the s key terms he had studied appeared. But 10 - k out of 100 - s key terms he hasn't studied appeared. Thus X is an Hypergeometric distribution, X~HGeom(s, 100 - s, 10) with PMF:

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Step-by-step explanation:

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out of which 16 are excited and the remaining 4 would be non-excited

Now the probability would be

$= \frac{^{16}C_2}{^{20}C_2}$

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A karaoke marked at ₽3,750 was sold for ₽3,225. What was the rate of discount?

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Step-by-step explanation:

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In the figure given below CP=x+3, PA=3x+19, CQ=x and QB=3x+4 then, what value of x will make PQ || AB?

zhenek [66]

Given that

PQ || AB

CP = x+3

PA = 3x+19

DC = x+3

CA = x

QB = 3x+4

We know that

By Basic Proportionality Theorem,

CP / PA = CQ / QB

On substituting these values in the above formula

⇛ (3x+19) / (x+3) = (3x+4) / x

On applying cross multiplication then

⇛ x(3x+19) = (3x+4)(x+3)

⇛ 3x²+19x = 3x(x+3)+4(x+3)

⇛ 3x²+19x = 3x²+9x+4x+12

⇛ 3x²+19x = 3x²+13x+12

⇛ 3x²+19x-3x²-13x = 12

⇛ (3x²-3x²)+(19x-13x) = 12

⇛ 0+6x = 12

⇛ 6x = 12

⇛ x = 12/6

⇛ x = 2

∴ , x = 2

Answer: The value of x for the given problem is 2

Additional comment:

Basic Proportionality Theorem

" A line drawn parallel to the one side of a triangle intersecting other two sides at two different points, then the line divides the other two sides in the same ratio".

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