Area of right-angled triangle is given by;
Area, A = 1/2 *b*h, Where b=base, h=height
Therefore,
A1 = 1/2bh = 16 in^2
A2 = 1/2 (2b)(2h) = 2bh
Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
2 6/7 * 4/5....turn ur mixed number into an improper fraction and just multiply
20 / 7 * 4 / 5 = 80/35 which reduces to 16/7 or 2 2/7
Answer= $138.98
47.86-25.20+52.75-22.04-8.50+94.11=$138.98
Answer:
(x+8)^2+y^2=16
Step-by-step explanation:
The equation for a circle in center-radius form is
(x-h)^2+(y-k)^2=r^2
where (h,k) is the center and r is the radius.
We are given the diameter is 8 so the radius is 8/2=4.
We are also given (h,k) is (-8,0).
The equation for the circle is
(x--8)^2+(y-0)^2=4^2
(x+8)^2+y^2=16
