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3 years ago

What is radical 50 - radical 2

Mathematics

2 answers:

ella [17]3 years ago

8 0

Answer:

4 sqrt(2)

Step-by-step explanation:

radical 50 - radical 2

I rewrite in terms of sqrt (means the same thing)

sqrt(50) - sqrt(2)

sqrt(25*2) - sqrt(2)

We know that sqrt (ab) = sqrt(a) sqrt(b)

sqrt(25)sqrt(2) - sqrt(2)

5sqrt(2) - sqrt(2)

Factor out the sqrt(2)

sqrt(2) (5-1)

4 sqrt(2)

Levart [38]3 years ago

4 0

Answer:

4√2

Step-by-step explanation:

To get √50 - √2, we need to simplify the √50. We can split the √50 into two factors, these being 2 and 25. Now, we have √2x25. The 25 is a perfect square, with 5 being the square root. This means we can put the 5 outside of the radical and remove the 25, leaving us with 5√2. Now we still need to subtract √2. This works similarly to subtracting something such as 5x-x. Because our radicals are the same, we can just subtract the √2 and have 4√2.

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2 years ago

I’ll mark brainest! Find all the real cube roots of -0.000125

Ymorist [56]

Answer:

-0.05

Step-by-step explanation:

This will become much easier if we can get the ugly decimal into a nice fraction form.

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3 years ago

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Read 2 more answers

1 over the square root of 8 = 4^(m − 2)?

andrew11 [14]

Answer:

5.5

Step-by-step explanation:

$\frac{1}{ \sqrt{8} } = {4}^{(m - 2)} \\$

Squaring both sides

$\frac{1}{8} = {4}^{2(m - 2)} \\ \frac{1}{8} = {4}^{2} \times {4}^{(m - 2)} \\ \frac{1}{8 \times {4}^{2} } = {4}^{(m - 2)} \\ \frac{1}{8 \times 16} = {4}^{(m - 2)} \\ \frac{1}{128} = {4}^{(m - 2)} \\ log_{4}(128) = (m - 2) \\ \frac{7}{2} = m - 2 \\ m = \frac{11}{2} = 5.5$

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4 years ago

Figure ABCD is a parallelogram, if point C lies on the line x = -1, what is the y value of point c?

brilliants [131]

Answer:

y = 0

Step-by-step explanation:

A parallelogram is a quadrilateral with opposite sides parallel. Then segment CD must be parallel to AB, and CB must be parallel to DA. Two different segments are parallel if they have the same slope.

slope of DA = (yA - yD)/(xA - xD) = (4 - 2)/(1 - (-1)) = 1

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Note: coordinates of A are (xA, yA), of B are (xB, yB), of C are (xC, yC) and of D are (xD, yD)

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