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andreev551 [17]
2 years ago
11

What is radical 50 - radical 2

Mathematics
2 answers:
ella [17]2 years ago
8 0

Answer:

4 sqrt(2)

Step-by-step explanation:

radical 50 - radical 2

I rewrite in terms of sqrt  (means the same thing)

sqrt(50) - sqrt(2)

sqrt(25*2) - sqrt(2)

We know that sqrt (ab) = sqrt(a) sqrt(b)

sqrt(25)sqrt(2) - sqrt(2)

5sqrt(2) - sqrt(2)

Factor out the sqrt(2)

sqrt(2) (5-1)

4 sqrt(2)

Levart [38]2 years ago
4 0

Answer:

4√2

Step-by-step explanation:

To get √50 - √2, we need to simplify the √50. We can split the √50 into two factors, these being 2 and 25. Now, we have √2x25. The 25 is a perfect square, with 5 being the square root. This means we can put the 5 outside of the radical and remove the 25, leaving us with 5√2. Now we still need to subtract √2. This works similarly to subtracting something such as 5x-x. Because our radicals are the same, we can just subtract the √2 and have 4√2.

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Licemer1 [7]
You will need to set equations to solve for x and y coordinate.
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5 0
3 years ago
Arturo, Pedro y Jorge son hermanos y duermen en la misma habitación. Su padre compró pintura para que entre los tres pinten su c
mr Goodwill [35]

Answer:

Tanto Pedro como Jorge deberán pintar 1/4 de la habitación cada uno.

Step-by-step explanation:

Dado que el cuarto entero es igual a 1, y que Arturo por ser el mayor de los hermanos tiene que pintar 1/2 de él, la parte que falta pintar es igual a 1/2 restante.

De ese 1/2, los hermanos menores, Pedro y Jorge, deben pintar dicha fracción en partes iguales. Por lo tanto, dado que (1/2) / 2 es igual a 1/4, la fracción que tanto Pedro como Jorge deberán pintar es de 1/4 de la habitación.

4 0
3 years ago
Read 2 more answers
19.25 divided by 3.5
Colt1911 [192]

Answer:

It would be 5.5

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4 0
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At most, how many unique roots will a third-degree polynomial function have?
beks73 [17]

The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.

In fact, if you use complex number, then a polynomial with degree n has exactly n roots.

So, in particular, a third-degree polynomial can have at most 3 roots.

In fact, in general, if the polynomial p(x) has solutions x_1,\ x_2,\ldots x_n, then you can factor it as

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So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as

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7 0
3 years ago
1 Point
Anastasy [175]

Answer:

61%

Step-by-step explanation:

it's really simple just take the percentage of both numbers, 42% and 19% and add them together and whatever the sum is, is gonna be your answer!

5 0
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