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Digiron [165]
3 years ago
14

definition of implication: why does P(x) v Q(x) become ~Q(x) -> P(x) rather than ~P(x) -> Q(x)?

Mathematics
1 answer:
insens350 [35]3 years ago
6 0
The easiest way to prove equivalence is to draw out a truth table and then compare the values. I'm going to show a truth table using proposition logic, it's the same result as using predicate logic. 
P(x) v Q(x)

P |Q || PvQ  || ~Q->P  <----Notice how this column matches the PvQ but if you were to 
---|---||--------||----------  <----continue the truth table with ~P->Q it would not be equivalent
T   T      T           T   
T   F      T           T
F   T      T           T
F   F      F           F

Let me know if you would like an example, if the truth table doesn't help. 
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(02.03 MC) The figure shows two triangles on a coordinate grid: A coordinate grid is shown from positive 6 to negative 6 on the
Alekssandra [29.7K]

Answer:

Step-by-step explanation:

A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin

Step-by-step explanation:

The figure is obviously rotated 180°. If the rotation is first, the image would be in the 4th quadrant, where it would stay after translation downward.

If the translation is downward first, it would be in the 3rd quadrant, moving to the first quadrant after rotation by 180°. This is the apparent sequence of transformations:

7 0
2 years ago
1/4 + (-3/4)= <br> -4 1/2 + 2= <br> -8+ (-1 1/8) =
AlekseyPX
1/4+ (-3/4) = -0.5      

-4 1/2 +2= -2.5     

-8+ (-11/8)= -9.125    
4 0
3 years ago
Find the value of x in the equation below. 60 = 10 x​
Ede4ka [16]

Answer:

Just do 60 divided by 10

Step-by-step explanation:

60=10 x  10 times 6 = 60 so x=6

7 0
3 years ago
Read 2 more answers
I need help with both if you don’t mind
Anvisha [2.4K]
The first one is A and the second one is A
6 0
3 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
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