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Digiron [165]
3 years ago
14

definition of implication: why does P(x) v Q(x) become ~Q(x) -> P(x) rather than ~P(x) -> Q(x)?

Mathematics
1 answer:
insens350 [35]3 years ago
6 0
The easiest way to prove equivalence is to draw out a truth table and then compare the values. I'm going to show a truth table using proposition logic, it's the same result as using predicate logic. 
P(x) v Q(x)

P |Q || PvQ  || ~Q->P  <----Notice how this column matches the PvQ but if you were to 
---|---||--------||----------  <----continue the truth table with ~P->Q it would not be equivalent
T   T      T           T   
T   F      T           T
F   T      T           T
F   F      F           F

Let me know if you would like an example, if the truth table doesn't help. 
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Ari has a total of 22 coins consisting of pennies and nickels. The total value of the coins is $0.54.
anastassius [24]
Let n = the number of nickels that Ari has.
Let p = the number of pennies that Ari has.

The total number of coins she has is 22.

n + p = 22

We have our first equation... But we another one to solve this.

Each penny is going to be $0.01 and a nickel is work $0.05.

And the total is $0.54

Our second equation. 0.05n + 0.01p = 0.54

n + p = 22
0.05n + 0.01p = 0.54

Multiply the top by -0.05

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Substitute p back into the top equation.

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So, Ari has 8 nickels and 14 pennies.
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