System software falls into two categories: operating system software and ___

If a pedestrian begins to cross my path when i have the right of way

Daniel [21]

What exactly is your question?? If you are driving all pedestrians have the right way.....treat all intersections as a crosswalk painted or not!!!

3 0

3 years ago

opearating system protection refers to a mechanism for controling access by programs, processes, or users to both system and use

Alekssandra [29.7K]

Answer:

The operating system must by the use of policies define access to and the use of all computer resources.

Policies are usually defined during the design of the system. These are usually default in settings. Others are defined and or modified during installation of the addon and or third-party software.

Computer Security Policies are used to exact the nature and use of an organisations computers systems. IT Policies are divided into 5 classes namely:

General Policies
Server Policies
VPN Policies
Back-Up Policies
Firewall Access and Configuration Policies

Cheers!

5 0

3 years ago

9.11: Array Expander

vodka [1.7K]

The Array Expander is an illustration of arrays and functions.

Arrays are variables that stores multiple values
Functions are named statements that are executed when called

<h3>The Array Expander program </h3>

The Array Expander program written in C++, where comments are used to explain each action is as follows:

#include <iostream>

using namespace std;

//This declares the Array Expander function

int* ArrayExpander(int *oldArr, int size){

//This declares the new array

int *newArr = new int[size * 2];

//This iteration sets values into the new array

for (int i = 0; i < size * 2; i++) {

if(i < size){

*(newArr+i) = *(oldArr+i);

}

else{

*(newArr+i) = 0;

}

//This returns a pointer to the new array

return newArr;

}

//The main method begins here

int main(){

//This declares the length of the array, N

int N;

//This gets input for N

cin>>N;

int initArr[N];

//If N is between 1 and 50

if(N > 0 && N <=50){

//This iteration gets values for the array

for(int i = 0; i<N; i++){

cin>>initArr[i];

}

//This calls the Array Expander function

int *ptr = ArrayExpander(initArr, N);

//This iteration prints the elements of the new array

for (int i = 0; i < N*2; i++) {

cout << ptr[i] << " ";

}

return 0;

}

Read more abou C++ programs at:

brainly.com/question/27246607

3 0

2 years ago

Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working alone, one machine would take one hour long

Alborosie

<em><u>Answer</u></em>

5 hours

<em><u>Explanation</u></em>

The two working together can finish a job in

$\frac{20}{9} \: hours$

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

$\frac{1}{x} + \frac{1}{x - 1}$

This should be equal to 20/9 hours.

$\frac{1}{x} + \frac{1}{x - 1} = \frac{9}{20}$

Multiply through by;

$20x(x - 1) \times \frac{1}{x} +20x(x - 1) \times \frac{1}{x - 1} = 20x(x - 1) \times \frac{9}{0}$

$20(x - 1) +20x = 9x(x - 1)$

$20x - 20+20x = 9{x}^{2} - 9x$

$9{x}^{2} - 9x - 20x - 20x + 20= 0$

$9{x}^{2} - 49x + 20= 0$

Factor to get:

$(9x - 4)(x - 5) = 0$

$x = \frac{4}{9} \: or \: x = 5$

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0

3 years ago

What can be said about the equipment used by photographers during the Civil War?

lilavasa [31]

The answer is 1 and 4

6 0

3 years ago

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System software falls into two categories: operating system software and ____ programs.â