Using polynomial long division, we get
3x^3+6x^2+11x
_____________
(x+2) | 3x^4-x^2+cx-2
-(3x^4+6x^3)
____________
6x^3-x^2+cx-2
- (6x^3+12x^2)
_____________
11x^2+cx-2
-(11x^2+22x)
__________
(22+c)x-2.
If you're wondering how I did the long division, what I essentially did was get the first value (at the start, it was 3x^4) and divided it by the first value of the divisor (which in x+2 was x) to get 3x^3 in our example. I then subtracted the polynomial by the whole divisor multiplied by, for example, 3x^3 and repeated the process.
For this to be a perfect factor, (x+2)*something must be equal to (22+c)x-2. Focusing on how to cancel out the 2, we have to add 2 to it. To add 2 to it, we have to multiply (x+2) by 1. However, there's a catch, which is that we subtract whatever we multiply (x+2) by, so we have to multiply it by -1 instead. We still need to cross out (22+c)x. Multiplying (x+2) by -1, we get
(-x-2) but by subtracting the whole thing from something means that we have to add -(-x-2)=x+2 to something to get 0. x+2-x-2=0, xo (22+c)x-2 must equal -x-2, meaning that (22+c)=-1 and c=-23
P, whatever the top letter is, m
Answer:
3,7,11,15
Step-by-step explanation:
1) 3
2) 3+4=7
3) 7+4=11
4) 11+4=15
{2, 3, 3, 1, 4, 1, 45, 76, 78, 73, 74, 79, 76}
Vlad1618 [11]
Answer:
Mean-39.6
Mode- 1,3,76
Median-45
MOC- 45
Step-by-step explanation
I got the mean by adding all of the numbers up and then dividing them by 13.
I got the mode because those numbers occur the most often.
I got the median by putting the numbers in order from least to greatest then picking the middle number.
I got the measure of center because there is not an outlier so you would use the median. If there was an outlier then you would use the mean.
