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3 years ago

How many different pairs of marker can be formed if you have one yellow,one red ,one green ,one blue,and one purple marker?

Mathematics

1 answer:

Marianna [84]3 years ago

4 0

4 different pairs of marker combinations can be formed

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Entomologists estimate that an average person consumed almost a pound of bug parts each year. There are that many insect eggs, l

gregori [183]

Answer:

0.9797

Step-by-step explanation:

We have X = number of insects in the 25bgrams of butter

Then the legal limit of concentration in peanut butter = 30 fragments/ 100 grams

Then insect amount in 25 grams =

E(X) = 30/100 x 25

= 0.3 x 25

= 7.5 fragments of insects

Using the poisson function in Excel, the probability of at least 3 crunchy critters

1 - p(X<=2)

p(X<=2) = POISSON (2, 7.5, TRUE) = 0.020156715

1 - 0.020156715

= 0.9797

7 0

2 years ago

Find the equation (in terms of x) of the line through the points (-2,3) and (4,-9)<br> y =

shepuryov [24]

Answer:

y =5

Step-by-step explanation:

−9−7

5−5

−16

y=mx+b

5=(0)(7)+b

b=5

therefore y = 5

3 0

2 years ago

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A dog runs from point O to B. The dog reaches A at 2.3 s into the sprint. Then the dog reaches C at 4.1 s. What is the average v

Pavlova-9 [17]

We are given

A dog runs from point O to B

t(OA)=2.3 s

t(OC)=4.1 s

now, we can find time between A and C

t(AC)=t(OC)-t(OA)

t(AC)=4.1-2.3

t(AC)=1.8 s

we are given

distance between A and C is 4m

so,

d=4m

now, we can find average velocity between A and C

$v=\frac{d}{t}$

we can plug values

$v=\frac{4}{1.8}$

$v=2.2m/s$

so, option-C..................Answer

6 0

3 years ago

A while back, either James borrowed $12 from his friend Rita or she borrowed $12 from him, but he can’t quite remember which. Ei

oksano4ka [1.4K]

The answer is x=42.8+- (plus or minus) 12

So he should either have $30.80 or $44.80 left

6 0

3 years ago

WILL MARK BRAINLIEST ASAP!!

7nadin3 [17]

$\dfrac{x^2+ax-4}{x+2}+\dfrac{x+b}{x+2}=\dfrac{x^2+ax-4+x+b}{x+2}=\dfrac{x^2+(a+1)x+(b-4)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=x+1\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x+1)(x+2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{(x)(x)+(x)(2)+(1)(x)+(1)(2)}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+2x+x+2}{x+2}\\\\\dfrac{x^2+(a+1)x+(b-4)}{x+2}=\dfrac{x^2+3x+2}{x+2}\iff a+1=3\ \wedge\ b-4=2\\\\\boxed{a=2\ \wedge\ b=6}$

3 0

3 years ago

Read 2 more answers