Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - 
Number of ways for second place - 
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place -
Number of ways for second place - 
Total number of different tickets are possible is
Therefore, 4032 different tickets are possible.
Answer:
b. 1/2
Step-by-step explanation:
lim (x -3)(x +2)
x-->-∞ ---------------
2x^2 + x +1
= lim (x^2 -3x +2x - 6)
x-->-∞ -----------------------
2x^2 + x +1
= lim (x^2 -x - 6)
x-->-∞ -----------------------
2x^2 + x +1
When we plug in x = -∞, we get indeterminate form.
Now we have to use the L'hospital rule.
d/dx (x^2 - x - 6) = 2x -1
d/dx (2x^2 + x + 1) = 4x + 1
Now apply the limit
lim (2x - 1) / (4x + 1)
x--->-∞
Here we have to degree of the numerator and the denominator of the same. In this case, if x --> -∞, we get the result as the coefficient of the leading term as the result.
According to the rule, we get
= 2/4
Which can simplified as 1/2
The answer is 1/2
Hope this will helpful.
Thank you.
Answer:
A = 41.4°
Step-by-step explanation:
Reference angle = A
Length of Adjacent side = 6
Length of Hypotenuse = 8
Apply the trigonometric function, CAH.
Cos A = Adj/Hyp
Substitute
A = 41.4° (approximated to the nearest tenth)
Answer:
86km/h
80km/h
Step-by-step explanation:
weighted average
bus took 5hrs so van took 3.75 hrs
300/3.75
6/48 simplified would be 1/8.
