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notsponge [240]
3 years ago
10

How do I get the area in this

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
You have to do 4x4 and you will get 16in2 but out the 2 in the corner of inches that your area
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X - Зу = -2<br> X - Зу = 16
Stells [14]
Answer: x - 3y = -2
x = -2 + 3y

x - 3y = 16
x = 16 + 3y

8 0
2 years ago
What is this simplified? Please help
Naya [18.7K]

Answer:

The end result is -1/(x + 1)

Step-by-step explanation:

In order to find the answer to this, we first need to factor the denominator. Since it is a quadratic, we try to find number that multiply to the last term (8) and add to the middle term (9). In this case, the numbers 8 and 1 would work. This allows us to use those numbers in parenthesis along with x as a fully factored form.

x^2 + 9x + 8 = (x + 1)(x + 8)

Now that we have this factored we can take the original equation and factor a -1 out of the top.

(-1)(x + 8)/(x + 1)(x + 8)

Since there is an (x + 8) on the top and bottom, we can cancel those.

-1/(x + 1)

6 0
3 years ago
Simplify. [6.6 ÷ (–5 + 3)] • (–1)
eimsori [14]
Hi there, we use PEMDAS to solve this problem, PEMDAS is parenthesis, Exponents, Multiply, Divide, Add, and Subtract. In this case, we have [6.6÷(-5+3)]*(-1), 6.6/-5+3(-1)=6.6/-2(-1)=(-3.3)(-1)=3.3. So, your answer is 3.3
8 0
3 years ago
If you are reading this please help!!!!
Soloha48 [4]

Given:

1.  -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$

To find:

The product of the polynomials.

Solution:

1. -3 x^{2}\left(4 x^{3}-7\right) =-3 x^{2}(4 x^{3}) -3 x^{2}(-7)

Multiply the numerical coefficient and add the powers of x.

                          =-12 x^{5}+21 x^{2}

2. (6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                              =12 x^2+18x-10 x-15

                              =12 x^2+8x-15

3. (3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

                                      =3x^{3}+15 x^2-6x-x^{2}-5 x+2

Add or subtract like terms together.

                                      =3x^{3}+14 x^2-11x+2

The answer for multiplying polynomials:

1. -12 x^{5}+21 x^{2}

2. \  12 x^2+8x-15

3. \ 3x^{3}+14 x^2-11x+2

3 0
3 years ago
What is -3x-32=-2(5-4x)
san4es73 [151]

Answer:

x=−2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3x−32=−2(5−4x)

−3x+−32=(−2)(5)+(−2)(−4x)(Distribute)

−3x+−32=−10+8x

−3x−32=8x−10

Step 2: Subtract 8x from both sides.

−3x−32−8x=8x−10−8x

−11x−32=−10

Step 3: Add 32 to both sides.

−11x−32+32=−10+32

−11x=22

Step 4: Divide both sides by -11.

−11x

−11

=

22

−11

5 0
3 years ago
Read 2 more answers
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